Answer:
Step-by-step explanation:
<u>Equations</u>
We have two cases where some variable is required to be found such that some condition is met. The first case is about finding the value of a that complies:
Rearranging
Factoring:
There are two solutions:
The second case requires us to find the value of x such that
Rearranging
This second-degree equation has no real roots. We'll offer the imaginary (complex) solutions:
Answer:
the confidence interval for the true weight of the specimen is;
4.1593 ≤ μ ≤ 4.1611
Step-by-step explanation:
We are given;
Standard deviation; σ = 0.001
Sample size; n = 8
Average weight; x¯ = 4.1602
We are given a 99% confidence interval and the z-value at this interval is 2.576
Formula for confidence interval is;
CI = x¯ ± (zσ/√n)
Plugging in the relevant values, we have;
CI = 4.1602 ± (2.576 × 0.001/√8)
CI = 4.1602 ± 0.000911
CI = (4.1602 - 0.000911), (4.1602 + 0.000911)
CI ≈ (4.1593, 4.1611)
Thus, the confidence interval for the true weight will be expressed as;
4.1593 ≤ μ ≤ 4.1611
Where μ represents the true weight
Answer:
the possible number would be 159 in
Step-by-step explanation:
Answer:
1145
Step-by-step explanation:
- <em>The upper bound is the smallest value that would round up to the next estimated value</em>.
Since the number was rounded to nearest ten, the upper bound is:
which rounds up to 1150 which is the next estimated value greater than 1140
If you wanted to write 4/10 as a decimal it would be .4
