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fredd [130]
3 years ago
10

6x=3(x - 4) - x plzz

Mathematics
2 answers:
Blababa [14]3 years ago
4 0

Answer:

-4

Step-by-step explanation:

6x = 3(x - 4)

6x = 3x - 12

3x = -12

x = -4

Best of Luck!

Rom4ik [11]3 years ago
3 0

Answer:

<h2>x = - 3</h2>

Step-by-step explanation:

6x=3(x - 4) - x

<u>Multiply the terms in the bracket</u>

That's

6x = 3x - 12 - x \\ 6x = 2x - 12

Subtract 2x from both sides of the <u>equation</u>

6x - 2x = 2x - 2x - 12 \\ 4x =  - 12

<u>Divide both sides by 4</u>

\frac{4x}{4}  =  -  \frac{12}{4}

We have the final answer as

<h3>x = - 3</h3>

Hope this helps you

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What is the 72nd term of -27, -11, 5
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Answer:

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Step-by-step explanation:

The first term is -27, and the common difference is 16.

The nth term is:

a = a₁ + d (n − 1)

a = -27 + 16 (n − 1)

a = -27 + 16n − 16

a = 16n − 43

The 72nd term is:

a = 16(72) − 43

a = 1109

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3 years ago
What times what makes 23
TiliK225 [7]
8 times 3 equals 23 and that is one of the answers



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How many different 6- player starting squads can be formed from a volleyball team of 11 players?
aivan3 [116]
You have to calculate how many combinations of 6 people can be chosen from 11.   The formula for this is:
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11 * 3 * 2 * 7 =
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7 0
3 years ago
Put the following equation of a line into slope-intercept form, simplifying all
Nataly [62]

Hi there! My Name is Alex! The Answer to your question is listed Below Hope this helps!

Answer:

y=-\frac{1}{6} x+3\\

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8 0
2 years ago
It is known that diskettes produced by a cer- tain company will be defective with probability .01, independently of each other.
zheka24 [161]

Answer:

1.27%

Step-by-step explanation:

To solve this problem, we may consider a binomial distribution where a customer can either accept or reject (and return) the diskette package.

Lets consider  some aspects:

1. From the formulation of the exercise we know that a package is accepted if it has at most 1 defective diskette. So our event A is defined as:

A = 0 or 1 defective diskette

2. The probability of a diskette being defective is 0.01

3. Each package contains 10 diskettes.

If X is defined as number of defective diskettes in the package, the probability of X is given by a binomial distribution with probability 0.01 and n=10

X ~ Bin(p=0.01, n=10)

Let us remember the calculation of probability for the binomial distribution:

P(X=x)=nCx*p^{x}*(1-p)^{(n-x)} with x = 0, 1, 2, 3,…, n

Where

n: number of independent trials

p: success probability  

x: number of successes in n trials

In our case success means finding a defective diskette, therefore

n=10

p=0.01

And for x we just need 0 or 1 defective diskette to reject the package

Hence,

P(X=x)=10Cx*0.01^{x}*(1-0.01)^{(10-x)} with x = 0, 1

So,

P(A)=P(X=0)+P(X=1)

P(A)=10C0*0.01^{0}*(1-0.01)^{(10-0)} + 10C1*0.01^{1}*(1-0.01)^{(9)}

P(A)=0.99^{10}+10*0.01*0.99^{9}

P(A)=0.9957

Now, because we have 3 packages and we might reject just 1 of them, we can find this probability like this:

3*(1-P(A))*P(A)*P(A) = (1-0.9957)*0.9957*0.9957=0.0127

Finally, we have that the probability of returning exactly one of the three packages is 1.27%

3 0
3 years ago
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