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9966 [12]
3 years ago
6

How much will the monthly payment be for a new car priced at $14,350 if the current finance rate is 36 months at 3. 16%? Include

financing the 8% TT&L and make a 30% down payment.
a)$279. 03

b)$325. 44

c)$305. 48

d)$436. 40

e)$398. 61
Mathematics
1 answer:
expeople1 [14]3 years ago
3 0

The monthly payment for the new car is; Choice A; $279. 03

<h3>Percentages</h3>

After the down payment of 30% and financing the 8% TT&L is made; it follows that;

The rest of the payment is;

  • $14,350(1 - 0.38)

  • $14,350(0.62)

Hence, $8,897 is the payment made over the course of the duration at a finance rate of 3.16%.

Ultimately, the monthly payment is; $8,897 × 0.0316 = $279.03

Read more on percentages;

brainly.com/question/1578533

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Step-by-step explanation:

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For the even numbers, 2 is the first term and 200 is the 100th term (because 2+(100-1)2 is equal to 200). So, (100(2+202)/2 = 10100.

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Can you guys please help me I will give you a point
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7 0
3 years ago
Suppose you have a light bulb that emits 50 watts of visible light. (Note: This is not the case for a standard 50-watt light bul
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Answer:

0.049168726 light-years

Step-by-step explanation:

The apparent brightness of a star is

\bf B=\displaystyle\frac{L}{4\pi d^2}

where

<em>L = luminosity of the star (related to the Sun) </em>

<em>d = distance in ly (light-years) </em>

The luminosity of Alpha Centauri A is 1.519 and its distance is 4.37 ly.

Hence the apparent brightness of  Alpha Centauri A is

\bf B=\displaystyle\frac{1.519}{4\pi (4.37)^2}=0.006329728

According to the inverse square law for light intensity

\bf \displaystyle\frac{I_1}{I_2}=\displaystyle\frac{d_2^2}{d_1^2}

where

\bf I_1= light intensity at distance \bf d_1  

\bf I_2= light intensity at distance \bf d_2  

Let \bf d_2  be the distance we would have to place the 50-watt bulb, then replacing in the formula

\bf \displaystyle\frac{0.006329728}{50}=\displaystyle\frac{d_2^2}{(4.37)^2}\Rightarrow\\\\\Rightarrow d_2^2=\displaystyle\frac{0.006329728*(4.37)^2}{50}\Rightarrow d_2^2=0.002417564\Rightarrow\\\\\Rightarrow d_2=\sqrt{0.002417564}=\boxed{0.049168726\;ly}

Remark: It is worth noticing that Alpha Centauri A, though is the nearest star to the Sun, is not visible to the naked eye.

7 0
3 years ago
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