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timama [110]
3 years ago
5

Help 15 pts. Please answer asap

Mathematics
2 answers:
Gnoma [55]3 years ago
5 0

Answer:

The answer is D.

Step-by-step explanation:

marta [7]3 years ago
4 0

Answer:

D. 4\sqrt{a^{2}+b^{2}}

Step-by-step explanation:

We can see the shape can be cut into 4 right triangles.  We can use pythagoreans theorem to find the length of the hypotenuse.  

The distance from 0 to a represents one side, and the distance from 0 to b represents the other side.

So

a^{2} +b^{2} =C^{2}

(C represents the hypotenuse)

So the hypotenuse can be written as \sqrt{a^{2} +b^{2} }

Since four of these lines make up the perimeter,

the total perimeter will be 4\sqrt{a^{2}+b^{2}}

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2. Ali is collecting signatures for a petition,
swat32

Step-by-step explanation:

Since the options are not clear enough, please kindly see the attached file for more explanation

7 0
3 years ago
Write an equation that has a graph with the shape of y = x^2, but shifted left 3 units.
svetoff [14.1K]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}\\\\
--------------------\\\\

\bf % template detailing
\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\left. \qquad  \right. if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\

\bf \bullet \textit{ vertical shift by }{{  D}}\\
\left. \qquad  \right. if\ {{  D}}\textit{ is negative, downwards}\\\\
\left. \qquad  \right. if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}

now, with that template in mind, let's see

\bf y=x^2\implies 
\begin{array}{llll}
y=(&1x&-0)^2\\
&B&C
\end{array}

so, just change C to +3, thus C/B is 3/1
6 0
3 years ago
I Need the answer for these 3
11111nata11111 [884]

Here you go enjoy

Have a good rest of your night

5 0
2 years ago
Which graph shows a negative rate of change for the interval 0 to 2 on the x-axis?
valentina_108 [34]

It seems that the four graphs are the same and they do not have a negative change rate in the interval 0 to 2 in the x-axis.

A negative change rate means that when x increases the value of the function (y) decreases; this is, the function is decreasing in the interval being estudied, which is the same that going downward.

So, you must look for in your graphs where the equation is going downward.

For example, in the graph attached, that happens in any interval from negative infitity to  1.5.

The vertex will help you to identify it.

Given that the graph goes downward from negative infinity to the vertex, any interval that includes that range will have negative change.

You must look for a parabola that opens upward and whose vertex is in x = 2.

Read more on Brainly.com - brainly.com/question/3774202#readmore

5 0
3 years ago
Read 2 more answers
Suppose that x and y vary inversely and that y = 5 when x = 1. What is y when x = 15?
LiRa [457]

Answer:

Y=1/3

Step-by-step explanation:

X=k/y

So let's make k the subject of formula

k=xy

x=1,y=5

So let's substitute

k=1×5

k=5

So we are to determine the value for y when x is 15

So let's solve

Y=k/x

Y=5/15

Y=1/3

Y=0.333333~0.3

7 0
3 years ago
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