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2 years ago

HELP PLEASE AND SHOW WORK!!!

Mathematics

1 answer:

lana66690 [7]2 years ago

5 0

Answer:

awnser is A

Step-by-step explanation:

Multiply all sides by 2 then add then up and you get 432.

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Simply the fraction <br><br> 21wx<br> 49xy

ddd [48]

$\frac{3w}{7y}$
this is the answer

3 0

3 years ago

Use the point-slope form linear equation given.

Agata [3.3K]

y-3=3(x+1)

opening the bracket

y-3=3x+3

y=3x+3+3

equation of the line in the form y=mx+c;

y=3x+6

therefore gradient=3

parallel lines have same gradient therefore gradient of the other line is 3

y--3/x-0=3

y+3=3(x-0)

y+3=3x-0

y=3x-3.

8 0

2 years ago

Tom bought 3 gallons of grey paint and 2 gallons of red paint. Grey paint is $24.59 per gallon and red paint is $37.99 per gallo

tigry1 [53]

Answer:

The red will cost him more by $2.21

Step-by-step explanation:

First you multiply the amount of gallons of grey paint and the cost and you get 24.59 x 3= 73.77

The do the same for red

37.99 x 2= 75.98

the red is going to cost him more by 75.98-73.77= $2.21

6 0

3 years ago

<img src="https://tex.z-dn.net/?f=5x%5E%7B2%7D%20%2B11x%2B2%3D0" id="TexFormula1" title="5x^{2} +11x+2=0" alt="5x^{2} +11x+2=0"

eimsori [14]

The solutions to the quadratic equation in the exact form are x = -1/2 or x = -5

<h3>What are quadratic equations?</h3>

Quadratic equations are second-order polynomial equations and they have the form y = ax^2 + bx + c or y = a(x - h)^2 + k

<h3>How to determine the solution to the quadratic equation?</h3>

A quadratic equations can be split to several equations and it can be solved as a whole

In this case, the quadratic equation is given as

5x^2 + 11x + 2 = 0

Using the form of the quadratic equation y = ax^2 + bx + c, we have

a = 5, b = 11 and c = 2

The quadratic equation can be solved using the following formula

x = (-b ± √(b^2 - 4ac))/2a

Substitute the known values of a, b and c in the above equation

x = (-11 ± √(11^2 - 4 * 5 * 2))/2*2

Evaluate the exponent

x = (-11 ± √(121 - 4 * 5 * 2))/2*2

Evaluate the products

x = (-11 ± √(121 - 40))/4

Evaluate the sum

x = (-11 ± √(81))/4

Take the square root of 81

x = (-11 ± 9)/4

Expand

x = 1/4 * (-11 + 9) or x = 1/4 * (-11 - 9)

Evaluate the difference

x = 1/4 * -2 or x = 1/4 * -20

Evaluate the product

x = -1/2 or x = -5

Hence, the solutions to the quadratic equation in the exact form are x = -1/2 or x = -5

Read more about quadratic equations at

brainly.com/question/1214333

#SPJ1

4 0

2 years ago

Rafeeq bought a field in the form of a quadrilateral (ABCD)whose sides taken in order are respectively equal to 192m, 576m,228m,

Valentin [98]

Answer:

a. 85974 m²

b. 17,194,800 AED

c. 18,450 AED

Step-by-step explanation:

The sides of the quadrilateral are given as follows;

AB = 192 m

BC = 576 m

CD = 228 m

DA = 480 m

Length of a diagonal AC = 672 m

a. We note that the area of the quadrilateral consists of the area of the two triangles (ΔABC and ΔACD) formed on opposite sides of the diagonal

The semi-perimeter, s₁, of ΔABC is found as follows;

s₁ = (AB + BC + AC)/2 = (192 + 576 + 672)/2 = 1440/2 = 720

The area, A₁, of ΔABC is given as follows;

$Area\, of \, \Delta ABC = \sqrt{s_1\cdot (s_1 - AB)\cdot (s_1-BC)\cdot (s_1 - AC)}$

$Area\, of \, \Delta ABC = \sqrt{720 \times (720 - 192)\times (720-576)\times (720 - 672)}$

$Area\, of \, \Delta ABC = \sqrt{720 \times 528 \times 144 \times 48}$ = 6912·√(55) m²

Similarly, area, A₂, of ΔACD is given as follows;

$Area\, of \, \Delta ACD= \sqrt{s_2\cdot (s_2 - AC)\cdot (s_2-CD)\cdot (s_2 - DA)}$

The semi-perimeter, s₂, of ΔABC is found as follows;

s₂ = (AC + CD + D)/2 = (672 + 228 + 480)/2 = 690 m

We therefore have;

$Area\, of \, \Delta ACD = \sqrt{690 \times (690 - 672)\times (690 -228)\times (690 - 480)}$

$Area\, of \, \Delta ACD = \sqrt{690 \times 18\times 462\times 210} = \sqrt{1204988400} = 1260\cdot \sqrt{759} \ m^2$

Therefore, the area of the quadrilateral ABCD = A₁ + A₂ = 6912×√(55) + 1260·√(759) = 85973.71 m² ≈ 85974 m² to the nearest meter square

b. Whereby the cost of 1 meter square land = 200 AED, we have;

Total cost of the land = 200 × 85974 = 17,194,800 AED

c. Whereby the cost of fencing 1 m = 12.50 AED, we have;

Total perimeter of the land = 576 + 192 + 480 + 228 = 1,476 m

The total cost of the fencing the land = 12.5 × 1476 = 18,450 AED

4 0

3 years ago