Answer:
(a) 0.0885 M
(b) 1.25
Step-by-step explanation:
Solute S has a partition coefficient of 5.9 between water (phase 1) and hexane (phase 2).
i.e Partition coefficient Kd = [S(hexane]/[S(water) = 5.9
to calculate the concentration of S in hexane; we have;
[S(hexane]/0.015 = 5.9
[S(hexane)] = 5.9 x 0.015
= 0.0885 M
Question B say ,
If the volume of water is 85.0 mL
and the volume of hexane is 18.0 mL,
to find the quotient (mol S in hexane/mol S in water), we will multiply the
Partition coefficient Kd with volume of hexane divided by volume of water
i.e Partition coefficient Kd = (moles/volume of S in hexane)/(moles/volume of S in water)
∴
(moles of S in hexane/moles of S in water) = Kd x (volume of hexane/volume of water)
= 5.9 x 18.0/85.0
= 1.25
