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2 years ago

11. Given a matrix A, what is A^1?A=[0 12 0 1]

Mathematics

1 answer:

pogonyaev2 years ago

3 0

$\text{Since det(A) = 0, the inverse of the matrix does not exist.}$

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Albertson's found that the demand for Coke products varies inversely as the price of the product. When the price of a Coke produ

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Answer:

859

Step-by-step explanation:

The demand for Coke products varies inversely as the price of Cole products.

Mathematically:

D α 1/p

Where D = demand, p = price of coke product

D = k/p

Where k = constant of proportionality.

Let us find k.

k = D * p

When Demand, D, is 1250, price, p, is $2.75:

=> k = 1250 * 2.75

k = $3437.5

Now, when price, p, is $4, the demand will be:

D = 3437.5/4

D = 859.375 = 859 (rounding to whole number)

The demand for the product is 859 when the price is $4.

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3 years ago

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2 years ago

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3 years ago

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3 years ago

The Pew Research Center reported that 73% of Americans who own a cell phone also use text messaging. In a recent local survey, 1

AnnZ [28]

Answer:

$z=\frac{0.775 -0.73}{\sqrt{\frac{0.73(1-0.73)}{200}}}=1.433$

Now we can find the p value. Since we have a bilateral test the p value would be:

$p_v =2*P(z>1.433)=0.152$

Since the p value is higher than the significance level of 0.1 we have enough evidence to FAIL to reject the null hypothesis and the best conclusion for this case would be:

Do Not reject H0

Step-by-step explanation:

Information provided

n=200 represent the sample size slected

X=155 represent the cell phone owners used text messaging

$\hat p=\frac{155}{200}=0.775$ estimated proportion of cell phone owners used text messaging

$p_o=0.73$ is the value to verify

$\alpha=0.1$ represent the significance level

We need to conduct a z test for a proportion

z would represent the statistic

$p_v$ represent the p value

System of hypothesis

We want to verify if the true proportion of cell phone owners used text messaging is different from 0.73 so then the system of hypothesis are:

Null hypothesis: $p=0.73$

Alternative hypothesis: $p \neq 0.73$

The statistic to check this hypothesis is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing the data given we got:

$z=\frac{0.775 -0.73}{\sqrt{\frac{0.73(1-0.73)}{200}}}=1.433$

Now we can find the p value. Since we have a bilateral test the p value would be:

$p_v =2*P(z>1.433)=0.152$

Since the p value is higher than the significance level of 0.1 we have enough evidence to FAIL to reject the null hypothesis and the best conclusion for this case would be:

Do Not reject H0

6 0

3 years ago

11. Given a matrix A, what is A^1?A=[0 12 0 1]​

11. Given a matrix A, what is A^1?A=[0 12 0 1]