What is the period of this graph?

Mathematics

1 answer:

SCORPION-xisa [38]3 years ago

4 0

Answer:

Period is time between the two peaks.

Period = 4.114 - 1.870

Period = 2.244 seconds

Step-by-step explanation:

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What is the volume of a rectangular prism with a length of 7m, a hight of 9m and a width of 11m

vazorg [7]

Hello!

To find the Volume of the Rectangular Prism, you'll need to multiply all of the measurements together. So you'll need to multiply 7, 9, and 11 together.

V=7*9*11

First, you'll need to multiply 7 and 9. Once you've multiplied 9 and 7 together, you should have 63. Now you should multiply 63 and 11 together. Once you've multiplied 63 and 11 together, you should have a Volume of 693

You should have a Volume of 693m³

I hope this helps!

5 0

3 years ago

A is inversely proportional to b. If a=7.2 when b=-4, what will a equal when b=6?

Tpy6a [65]

Answer:

Step-by-step explanation:

To find the value of a when b=6 we must first find the relationship between them.

The statement

a is inversely proportional to b is written as

$a \: \: \alpha \: \: \frac{k}{b}$

where k is the constant of proportionality

When a = 7.2 , b = -4

So we have

$7.2= \frac{k}{ - 4}$

k = 7.2 × - 4

k = - 28.8

So the formula for the variation is

$a = - \frac{28.8}{b}$

When

b = 6

That's

$a = - \frac{28.8}{6}$

We have the final answer as

Hope this helps you

7 0

3 years ago

How to solve this?<br>\int \frac { 4 - 3 x ^ { 2 } } { ( 3 x ^ { 2 } + 4 ) ^ { 2 } } d x

ivanzaharov [21]

$\Large \mathbb{SOLUTION:}$

$\begin{array}{l} \displaystyle \int \dfrac{4 - 3x^2}{(3x^2 + 4)^2} dx \\ \\ = \displaystyle \int \dfrac{4 - 3x^2}{x^2\left(3x + \dfrac{4}{x}\right)^2} dx \\ \\ = \displaystyle \int \dfrac{\dfrac{4}{x^2} - 3}{\left(3x + \dfrac{4}{x}\right)^2} dx \\ \\ \text{Let }u = 3x + \dfrac{4}{x} \implies du = \left(3 - \dfrac{4}{x^2}\right)\ dx \\ \\ \text{So the integral becomes} \\ \\ = \displaystyle -\int \dfrac{du}{u^2} \\ \\ = -\dfrac{u^{-2 + 1}}{-2 + 1} + C \\ \\ = \dfrac{1}{u} + C \\ \\ = \dfrac{1}{3x + \dfrac{4}{x}} + C \\ \\ = \boxed{\dfrac{x}{3x^2 + 4} + C}\end{array}$