Answer:
B. -4.
Step-by-step explanation:
Answer:
First since 2 of the options ask for the width of BM lets solve for it using the Pythagorean theorem for both sides of point L:
a² + b² = c²
30² + b² = 50²
b² = 50² - 30²
b² = 1600
b = 40 Line BL = 40 ft
Since the ladder is 50 feet it is the same length on the other side as well
a² + b² = c²
40² + b² = 50²
b² = 50² - 40²
b² = 900
b = 30 line LM is 30 ft
SO line lm + line bl = 30 + 40 = 70 ft
A is true because ^
B isn't true because as we solved for earlier, BL is 40
C is true because line LM is in fact 30 ft as we solved for
D is not true because as we said earlier BM is 70
E is true because the same ladder was used on both sides of the street
Step-by-step explanation:
Answer:
x=8
Step-by-step explanation:
Answer:
b. about 63.9 units and 41.0 units
Step-by-step explanation:
In question ∠a= 29° and Side of a= 15 and b= 20
Using sine rule of congruence of triangle.
⇒ 
⇒ 
Using value of sin 29°
⇒ 
Cross multiplying both side.
⇒ Sin B= 
∴ B= 41°
Now, we have the degree for ∠B= 41°.
Next, lets find the ∠C
∵ we know the sum total of angle of triangle is 180°
∴∠A+∠B+∠C= 180°
⇒ 
subtracting both side by 70°
∴∠C= 110°
Now, again using the sine rule to find the side of c.

⇒
Using the value of sine and cross multiplying both side.
⇒ C= 
∴ Side C= 28.92.
Now, finding perimeter of angle of triangle
Perimeter of triangle= a+b+c
Perimeter of triangle= 
∴ Perimeter of triangle= 63.9 units
Answer:
d 70%
Step-by-step explanation:
30 students in class
21 students with 5+ vowels
21/30 x 100 = 70%