what math is this could you tell me what math this is plz
5x - 2 equivalent to to 2x−2+3x
answer is B. 2x−2+3x
Answer:
The probability that a container will be shipped even though it contains 2 defectives if the sample size is 88, will be 
Step-by-step explanation:
The first step is to count the number of total possible random sets of taking a sample size of 88 engines over 1212 engines of the population, so ![\left[\begin{array}{ccc}1212\\88\end{array}\right] =1212C88=4.7205x10^{135}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1212%5C%5C88%5Cend%7Barray%7D%5Cright%5D%20%3D1212C88%3D4.7205x10%5E%7B135%7D)
The second step is to count the number of total possible random sets of taking a sample size of 88 engines over 1210 engines (discounting the 2 defective engines) as the possible ways to succeed, so ![\left[\begin{array}{ccc}1210\\88\end{array}\right] =1212C88=4.0596x10^{135}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1210%5C%5C88%5Cend%7Barray%7D%5Cright%5D%20%3D1212C88%3D4.0596x10%5E%7B135%7D)
Finally we need to compute 
, therefore the probability that a container will be shipped is
The number -33 divisors are:
D(-33) = {-33, -11, -3, -1, 1, 3, 11, 33}
a × b = -33
<u>1) -33 × 1 = -33 ⇒ Sum is: -33 + 1 = -32</u>
2) -11 × 3 = -33 ⇒ Sum is: -11 + 3 = -8
3) -3 × 11 = -33 ⇒ Sum is: -3 + 11 = 8
4) -1 × 33 = -33 ⇒ Sum is: -1 + 33 = 32
<u>5) 1 × (-33) = -33 ⇒ Sum is: 1 + (-33) = 1 - 33 = -32</u>
6) 3 × (-11) = -33 ⇒ Sum is: 3 + (-11) = 3 - 11 = -8
7) 11 × (-3) = -33 ⇒ Sum is: 11 + (-3) = 11 - 3 = 8
8) 33 × (-1) = -33 ⇒ Sum is: 33 + (-1) = 33 - 1 = 32
<h2>The least possible sum of a and b is -32</h2>
to 1) and to 5)
Answer:
x can be 3, -3, i, or -i.
Step-by-step explanation:
If you can't find the factoring by looking at this, simplify the equation.
let
x
2
=
y
to make things easier to see
Now we have
y
2
−
8
y
−
9
=
0
See it now?
We can factor into
(
y
−
9
)
(
y
+
1
)
Now substitute back in
x
2
for
y
.
(
x
2
−
9
)
(
x
2
+
1
)
Since
(
x
2
−
9
)
is a difference of two squares,
(
x
−
3
)
(
x
+
3
)
Now we have
(
x
−
3
)
(
x
+
3
)
(
x
2
+
1
)
x can be 3, -3 for the first two parts
x
2
+
1
=
0
can become
x
2
=
−
1
Taking the positive and negative root means
x
=
±
√
−
1
Thus
x
=
±
i
in addition to 3 and -3.
