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Tanzania [10]
3 years ago
15

Two integers a and b have a product of -33. What is the least possible sum of a and b

Mathematics
1 answer:
irga5000 [103]3 years ago
7 0

 

The number -33 divisors are:

D(-33) = {-33, -11, -3, -1, 1, 3, 11, 33}

a × b = -33

<u>1)  -33 × 1 = -33   ⇒   Sum is:   -33 + 1 = -32</u>

2)  -11 × 3 = -33   ⇒   Sum is:   -11 + 3 = -8

3)  -3 × 11 = -33   ⇒   Sum is:   -3 + 11 = 8

4)  -1 × 33 = -33   ⇒   Sum is:   -1 + 33 = 32

<u>5)  1 × (-33) = -33   ⇒   Sum is:   1 + (-33) = 1 - 33 = -32</u>

6)  3 × (-11) = -33   ⇒   Sum is:   3 + (-11) = 3 - 11 = -8

7)  11 × (-3) = -33   ⇒   Sum is:   11 + (-3) = 11 - 3 = 8

8)  33 × (-1) = -33   ⇒   Sum is:   33 + (-1) = 33 - 1 = 32

<h2>The least possible sum of a and b is  -32</h2>

to 1)  and to 5)



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Simplify the following expression. 3 2/5x3(-7/5)
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The simplified expression of 32/5 x 3(-7/5) is  -672/25

<h3>How to simplify the expression?</h3>

The mathematical expression is given as:

32/5 x 3(-7/5)

Evaluate the product of 3 and -7/5

32/5 x 3(-7/5) =  32/5 x -21/5

Evaluate the product of 32 and -21

32/5 x 3(-7/5) =  672/5 x -1/5

Evaluate the product of 5 and 5

32/5 x 3(-7/5) =  672/25 x -1

So, we have:

32/5 x 3(-7/5) =  -672/25

Hence, the simplified expression of 32/5 x 3(-7/5) is  -672/25

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2 years ago
The sum of two consecutive odd integers is 20 less than four times the smaller of the two integers. Which the following equation
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Answer:

consecutive = x+x+2

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Answer:

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