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brilliants [131]

3 years ago

10

If cosine theta almost-equals 0. 3090, which of the following represents approximate values of sine theta and tangent theta, for

0 degrees less-than theta less-than 90 degrees? sine theta almost-equals 0. 9511; tangent theta almost equals 0. 3249 sine theta almost-equals 0. 9511; tangent theta almost equals 3. 0780 sine theta almost-equals 3. 2362; tangent theta almost-equals 0. 0955 sine theta almost-equals 3. 2362; tangent theta almost-equals 10. 4731.

1 answer:

hoa [83]3 years ago

4 0

Sine theta almost-equals 0. 9511 and tangent theta will almost equals

3. 0780

<h3 /><h3>What are sin theta,cos theta, and tan theta in trigonometry?</h3>

It is given that-

The cosine theta have the value =0.3090.

We can be write as,

cos∅=0.9090

To find the value of theta, We will take cosine function of the value 0.3090

This will make the cosine angle as arc cosine. Thus,

∅= $COS^{-1}$ (0.3090)

Solve it further as,

∅=72°

Hence the value of the angle is 72 degrees.

Use this value to find the angle of sin theta and tangent theta.

The value of sine theta,

sin 72°=0.9511

Hence, the value of sine theta is 0.9511.

The value of tangent theta,

tan 72°=3.078.

Hence, the value of tangent theta is 3.078.

Hence,

The value of sine theta is 0.9511.

The value of tangent theta is 3.078.

To know more about the trigonometry angles here;

brainly.com/question/20519838

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3 years ago

Find a cubic function f(x) = ax^3 + bx^2 + cx + d that has a local maximum value of 3 at x = −3 and a local minimum value of 0 a

Ahat [919]

Answer:

f(x) = (3x³ + 9x² - 27x + 15)/32

Step-by-step explanation:

f'(x) = 3ax² + 2bx + c

Maximum or minimum: f'(x) = 0

Maximum: f'(-3) = 0 and f(-3) = 3

Minimum: f'(1) = 0 and f(1) = 0

f'(-3) = 0 leads 27a - 6b + c = 0 (1)

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(1) - (2): 24a - 8b = 0, or 3a - b = 0, b = 3a

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(1) * 4 + (5): 80a - 16b = 3,

use b = 3a, get 80a - 16*3a = 3, 32a = 3, a = 3/32, b = 3a = 9/32

From (2): c = -3a - 2b = -9/32 - 18/32 = -27/32

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So

f(x) = (3x³ + 9x² - 27x + 15)/32

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2 years ago

Algebra help - please be so kind - god bless. 2&3 please

azamat

2. -11 sq rt of 112
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3 years ago

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Answer:

Step-by-step explanation:

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Bringing like terms on one

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7 0

3 years ago

Read 2 more answers

A pen company averages 1.2 defective pens per carton produced (200 pens). The number of defects per carton is Poisson distribute

nlexa [21]

Answer:

a. P(x = 0 | λ = 1.2) = 0.301

b. P(x ≥ 8 | λ = 1.2) = 0.000

c. P(x > 5 | λ = 1.2) = 0.002

Step-by-step explanation:

If the number of defects per carton is Poisson distributed, with parameter 1.2 pens/carton, we can model the probability of k defects as:

$P(k)=\frac{\lambda^{k}e^{-\lambda}}{k!}= \frac{1.2^{k}\cdot e^{-1.2}}{k!}$

a. What is the probability of selecting a carton and finding no defective pens?

This happens for k=0, so the probability is:

$P(0)=\frac{1.2^{0}\cdot e^{-1.2}}{0!}=e^{-1.2}=0.301$

b. What is the probability of finding eight or more defective pens in a carton?

This can be calculated as one minus the probablity of having 7 or less defective pens.

$P(k\geq8)=1-P(k$

$P(0)=1.2^{0} \cdot e^{-1.2}/0!=1*0.3012/1=0.301\\\\P(1)=1.2^{1} \cdot e^{-1.2}/1!=1*0.3012/1=0.361\\\\P(2)=1.2^{2} \cdot e^{-1.2}/2!=1*0.3012/2=0.217\\\\P(3)=1.2^{3} \cdot e^{-1.2}/3!=2*0.3012/6=0.087\\\\P(4)=1.2^{4} \cdot e^{-1.2}/4!=2*0.3012/24=0.026\\\\P(5)=1.2^{5} \cdot e^{-1.2}/5!=2*0.3012/120=0.006\\\\P(6)=1.2^{6} \cdot e^{-1.2}/6!=3*0.3012/720=0.001\\\\P(7)=1.2^{7} \cdot e^{-1.2}/7!=4*0.3012/5040=0\\\\$

$P(k$

c. Suppose a purchaser of these pens will quit buying from the company if a carton contains more than five defective pens. What is the probability that a carton contains more than five defective pens?

We can calculate this as we did the previous question, but for k=5.

$P(k>5)=1-P(k\leq5)=1-\sum_{k=0}^5P(k)\\\\P(k>5)=1-(0.301+0.361+0.217+0.087+0.026+0.006)\\\\P(k>5)=1-0.998=0.002$

5 0

4 years ago