Twice a increased by the cube of a equals b :
2a + a^3 = b
Answer: 560 tickets
Step-by-step explanation:
3/4 = 420/x; now cross multiply:
3x = 4(420)
3x = 1,680; now divide both sides by 3, and you get x = 560
#1 30
#2 150
#3 110
#4 60
#5 2x+50+3x=180
combine like terms
5x+50=180
subtract 50 from both sides
5x=130
divide both sides by 5 to isolate the variable
x=26
#5 3x=3(26)=78
#6 2x+50=2(26)+50=102
#7 AGE and CHG, AGH and CHF, EGB and GHD, HGB and FHD
#8 AGE and FHD, CHF and EGB
From the diagram above,
XZ = 10 in and OX = 10 in
we are to find length of OY
XZ is a chord and line OY divides the chord into equal length
Hence, ZY=YX= 5 in
Now we solve the traingle OXY
To find OY we solve using pythagoras theorem
applying values from the triangle above
![\begin{gathered} OX^2=XY^2+OY^2 \\ 10^2=5^2+OY^2 \\ 100=25+OY^2 \\ OY^2\text{ = 100 -25} \\ OY^2\text{ = 75} \\ OY\text{ = }\sqrt[]{75} \\ OY\text{ = }\sqrt[]{25\text{ }\times\text{ 3}} \\ OY\text{ = 5}\sqrt[]{3\text{ }}in \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20OX%5E2%3DXY%5E2%2BOY%5E2%20%5C%5C%2010%5E2%3D5%5E2%2BOY%5E2%20%5C%5C%20100%3D25%2BOY%5E2%20%5C%5C%20OY%5E2%5Ctext%7B%20%3D%20100%20-25%7D%20%5C%5C%20OY%5E2%5Ctext%7B%20%3D%2075%7D%20%5C%5C%20OY%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B75%7D%20%5C%5C%20OY%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B25%5Ctext%7B%20%7D%5Ctimes%5Ctext%7B%203%7D%7D%20%5C%5C%20OY%5Ctext%7B%20%3D%205%7D%5Csqrt%5B%5D%7B3%5Ctext%7B%20%7D%7Din%20%5Cend%7Bgathered%7D)
Therefore,
Length of OY =
![5\sqrt[]{3}](https://tex.z-dn.net/?f=5%5Csqrt%5B%5D%7B3%7D)
Answer:
c is correct
Step-by-step explanation:
