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1 year ago

Find the perimeter of the figure to the nearest hundredth.

Mathematics

1 answer:

Eduardwww [97]1 year ago

6 0

50.26 in.

12 + 5 + 5 + (3.14 x 9)

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PLEASE HELP IM STRUGGLING!!!

Mnenie [13.5K]

Answer:

10. 0.99
11. -60
12. 5.5

Step-by-step explanation:

<u>Use the slope formula:</u>

m = (y2 - y1)/(x2 - x1)

10.

m = (6.24 - 3.27)/(5 - 2) = 2.97/3 = 0.99

11.

m = (240 - 360)/(3 - 1) = -120/2 = -60

12.

m = (8.84 - 6.09)/(7 - 2) = 2.75/5 = 5.5

6 0

2 years ago

6 poodles to 18 beagles

JulijaS [17]

Answer:WHY YOU CHEATING LOL

Step-by-step explanation:

3 0

2 years ago

70% of a number is 98.

hammer [34]

The solution is as follows:

Set up the proportion:

70% - 98
90% - x

70% / 90% = 98 / x

7 / 9 = 98 /x

(7 / 9) x = 98

x = 98 x 9/7

x = 14 x 9

x = 126

The answer is <span>D. 126.

I hope my answer has come to your help. God bless and have a nice day ahead!</span>

8 0

2 years ago

Please help would be appreciated

yKpoI14uk [10]

Answer:

The total volume of the whole figure is 576m³.

Step-by-step explanation:

First find the volume for the first figure.

Volume of a Rectangular Prism (formula): L•W•H

V = (15m)(12m)(2m)

V = 360m³

Now, find the volume for the second figure.

V = (6m)(12m)(3m)

V = 216m³

Finally, just add both volumes to find the total volume of the entire figure.

Vt = 216m³ + 360m³

Vt = 576m³

5 0

2 years ago

What is the distance between coordinates (-6.25,5) and (-3.75,2)

Oksi-84 [34.3K]

Answer:

$\sqrt{15.25}$

Step-by-step explanation:

To find the distance, we can use the distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ when the given points are $(x_1,y_1)$ and $(x_2,y_2)$

Plug in the points (-6.25,5) and (-3.75,2)

$d=\sqrt{(-6.25-x_1)^2+(5-y_1)^2}\\d=\sqrt{(-6.25-(-3.75))^2+(5-2)^2}\\d=\sqrt{(-6.25+3.75)^2+(5-2)^2}\\d=\sqrt{(-2.5)^2+(3)^2}\\d=\sqrt{6.25+9}\\d=\sqrt{15.25}$

Therefore, the distance between the two coordinates is $\sqrt{15.25}$ , or approximately 3.91.

I hope this helps!

6 0

2 years ago