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3 years ago

Solve for y- 4y−3=5y+2

2 answers:

6 0

Y=−5/8 which is the answer to the equation
To check plug in the y value and see if it equals out

Sergeeva-Olga [200]3 years ago

4 0

This is your problem: y-4y-3=5y+2. First, take y-4y and turn it in to -3y. Next, take 5y and put -5y instead. So your problem is looking like this so far: -3y-5y-3=2. Then, change -3 and turn it into a positive 3 at the end of the equation like this. -3y-5y=2+3. Then lets do -3y-5y which is -8y. Next, do 2+3 which is 5. Your problem looks like this -8y=5. Lastly, divide both sides of the equation by -8. Which means Y= -5/8. Hope this helps ;)

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Divide: 27÷77,868 Help

Contact [7]

Answer:

this is the answer unless you did it backwards

Step-by-step explanation:

3.467406380027739e-4

8 0

3 years ago

What is 18+(-8) + 11 simplified?

FromTheMoon [43]

18 + (-8) + 11

Adding a negative number is the same as subtracting a positive number. So "18-8" is the same thing as "18+ -8".

18 - 8 + 11

10 + 11

21

8 0

3 years ago

Suppose you carry out a significance test of h0: μ = 8 versus ha: μ > 8 based on sample size n = 25 and obtain t = 2. 15. Fin

OLEGan [10]

Using a t-distribution calculator and finding the p-value, the correct option regarding the conclusion is given by:

a) the p-value is 0.02. We reject h0 at the 5% significance level because the p-value 0.02 is less than 0.05.

<h3>What is the relation between the p-value and the conclusion?</h3>

It also involves the significance level, as follows.

If the p-value is less than the significance level, we reject the null hypothesis $h_0$ .

If it is more, we do not reject.

In this problem, a t-distribution calculator for a right-tailed with t = 2.15 and 25 - 1 = 24 df is used to find a p-value of 0.02.

It is less than 0.05, hence option a is correct.

More can be learned about p-values at brainly.com/question/26454209

5 0

2 years ago

Now there is a square city of unknown size with a gate at the center of each side. There is a tree 20 b from the north gate. Tha

Brums [2.3K]

Answer:

The length of each side of the city is 250b

Step-by-step explanation:

Given

$a = 20$ --- tree distance from north gate

$b =14$ --- movement from south gate

$c = 1775$ --- movement in west direction from (b)

See attachment for illustration

Required

Find x

To do this, we have:

$\triangle ADE \sim \triangle ACB$ --- similar triangles

So, we have the following equivalent ratios

$AE:DE = AB:CB$

Where:

$AE = 20\\ DE = x/2 \\ AB = 20 + x + 14 \\ CB = 1775$

Substitute these in the above equation

$20:x/2 = 20 + x + 14: 1775$

$20:x/2 = x + 34: 1775$

Express as fraction

$\frac{20}{x/2} = \frac{x + 34}{1775}$

$\frac{40}{x} = \frac{x + 34}{1775}$

Cross multiply

$x *(x + 34) = 1775 * 40$

Open bracket

$x^2 + 34x = 71000$

Rewrite as:

$x^2 + 34x - 71000 = 0$

Expand

$x^2 + 284x -250x - 71000 = 0$

Factorize

$x(x + 284) -250(x + 284)= 0$

Factor out x + 284

$(x - 250)(x + 284)= 0$

Split

$x - 250 = 0 \ or\ x + 284= 0$

Solve for x

$x = 250 \ or\ x =- 284$

x can't be negative;

So:

$x = 250$

6 0

3 years ago

A school P is 16km due west of a school Q. what is the bearing of Q from P

Irina-Kira [14]

Answer:

16Km due east of school P

Step-by-step explanation:

Given

A school P is 16km due west of a school Q

Thus, we can say that distance PQ = 16 km.

________________________________

now we have to find the bearing of Q from P

As distance is same

distance PQ = distance QP

Thus,

Distance will remain same of 16 km.

For direction,

If Q is west of P, then P will be east of Q $P------------------>Q$

as shown in figure P is west of Q,

now from point P , Q is west P.

Thus,

Bearing of School Q from P is 16Km due east of school P

7 0

3 years ago