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3 years ago

Please help me solve this problem

Mathematics

1 answer:

Alex3 years ago

8 0

The answer for this is X+2g= 0

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Dr. Caras was characterizing a cytochrome (an iron containing protein) from a new strain of bacteria. He obtained the following

olya-2409 [2.1K]

Answer:

0.5613

Step-by-step explanation:

Here mean strain of bacteria x = sum of all numbers/ total numbers = 0.5514 %

Standard deviation s = 0.0040 %

Test statistic

G = (x_{max} -x)/s = (0.5613 - 0.5514)/ 0.0040 = 2.475

95% confidence value for outlier for n = 8 and alpha = 0.05

G_{critical} = 2.1266

so here we see that G > G_critical , so we reject that the there is no outlier . the value of 0.5613 is and outlier.

7 0

3 years ago

CAN SOMEONE HELP ME PLZ NO LINKS

Vesnalui [34]

Answer:

length = 2w - 3

l = length

w = width

2(length) + 2(width) = perimeter

2(2w - 3) + 2(w) = 60

6w -6 =60

w = 11

len = 2(11) - 3

Step-by-step explanation:

3 0

3 years ago

Factor the expression. 24x+3

Olin [163]

Answer:

Step-by-step explanation:

24x = 3 * 8 * x

3 = 3 * 1

Greatest common factor = 3

24x +3 = 3*8x + 3*1

=3(8x + 1)

6 0

3 years ago

Read 2 more answers

Which ones do I choose

weeeeeb [17]

It should be B because is a minus is in front of something that is a negative they change to be positive

7 0

3 years ago

The class average on a math test was an 82 with a standard deviation of 5. If the

Alex787 [66]

Answer:

Option 3 and 4.

Step-by-step explanation:

The z score shows by how many standard deviations the raw score is above or below the mean. The z score is given by:

$z=\frac{x-\mu}{\sigma} \\\\where\ x=raw\ score,\mu=mean, \ \sigma=standard\ deviation$

Given that mean (μ) = 82, standard deviation (σ) = 5

1) For x = 74:

$z=\frac{x-\mu}{\sigma} \\\\z=\frac{74-82}{5} =-1.6$

Option 1 is incorrect

2) For x < 87

$z=\frac{x-\mu}{\sigma} \\\\z=\frac{87-82}{5} =1$

From the normal distribution table, P(x < 87) = P(z < 1) = 0.8413 = 84.13%

Option 2 is incorrect

3) For x = 95:

$z=\frac{x-\mu}{\sigma} \\\\z=\frac{95-82}{5} =2.6$

Option 3 is correct

4) For x < 77

$z=\frac{x-\mu}{\sigma} \\\\z=\frac{77-82}{5} =-1$

From the normal distribution table, P(x < 77) = P(z < -1) = 0.16 = 16%

Option 4 is correct

5) For x > 92

$z=\frac{x-\mu}{\sigma} \\\\z=\frac{92-82}{5} =2$

From the normal distribution table, P(x > 92) = P(z > 2) = 1 - P(z < -2) = 1 - 0.9772 = 0.0228 = 2.28%

Option 5 is incorrect

8 0

3 years ago