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zmey [24]
3 years ago
12

Please help me solve this problem

Mathematics
1 answer:
Alex3 years ago
8 0
The answer for this is X+2g= 0
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What is the greatest factor (GCF) of 24 and 40?
bagirrra123 [75]

Answer:

8

Step-by-step explanation:

that;'s what i put the first time

3 0
3 years ago
Read 2 more answers
Write two subtraction facts related to 7 + 5 =12​
Nezavi [6.7K]

Answer:

12-5=7

12-7=5

Step-by-step explanation:

5 0
3 years ago
The longest side of a triangle is 5 inches. Longer than the shortest side. The medium side is 4 inches. Longer than the shortest
Llana [10]

Answer:

The answer to your question is L = 10 in , M = 9 in ; S = 5 in

Step-by-step explanation:

Data

longest side = 5 + x in

medium side = 4 + x in

shortest side = x

Perimeter = 24 in

Process

1.- Write and equation to solve this problem

    Perimeter = longest side + medium side + shortest side

Substitution

             24 = (5 + x) + (4 + x) + x

Simplification

            24 = 5 + x + 4 + x + x

            24 = 9 + 3x

            24 - 9 = 3x

                  15 = 3x

                   x = 15/3

                   x = 5

2.- Calculate the lengths of the side

Longest side = 5 + 5 = 10 in

Medium side = 5 + 4 = 9 in

Shortest side = 5 in

6 0
3 years ago
Read 2 more answers
(Angles in
Bingel [31]

Answer:

m<ABC = 116°

m<CDE = 67°

Step-by-step explanation:

✔️m<ABC = 180 - m<BAD (adjacent angles of a parallelogram are supplementary)

m<ABC = 180 - 64° (Substitution)

m<ABC = 116°

✔️m<CDA = m<CDE + m<ADE (angle addition postulate)

m<CDA = m<CDE + 49°

m<CDA = m<ABC (opposite angles of a parallelogram are congruent)

m<CDE + 49° = 116° (substitution)

m<CDE = 116° - 49° (Substraction property of equality)

m<CDE = 67°

4 0
3 years ago
Twenty-four distinguishable balls are to be placed in six boxes.(DIFFERENT BOXES) (a) In how many different ways can this be don
zvonat [6]

Answer: a) 124,596, b) 2142691552.

Step-by-step explanation:

Since we have given that

Number of distinguishable balls = 24

Number of boxes = 6

(a) In how many different ways can this be done?

^{24}C_6\\\\=134,596

(b) In how many different ways can this be done if box 1 must get 12 balls, box 2 must get 7 balls, box 3 must get 5 balls, and boxes 4, 5, and 6 must be empty?

Number of ways would be

\dfrac{24!}{12!7!5!}=2142691552

Hence, a) 124,596, b) 2142691552.

3 0
3 years ago
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