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Marizza181 [45]
3 years ago
11

Which two integers is -410 between?

Mathematics
1 answer:
Ivenika [448]3 years ago
7 0

Answer:

-8 and -7

Step-by-step explanation:

First, let's find the cubed version of each answer choice.

-12 and -11:

  • -12 cubed = -1728
  • -11 cubed = -1331

-20 and -19:

  • -20 cubed = -8000
  • -19 cubed = -6859

-15 and -14:

  • -15 cubed = -3375
  • -14 cubed = -2744

-8 and -7:

  • -8 cubed = -512
  • -7 cubed = -343

Therefore, the answer is -8 and -7.

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What is the correct solution process for (x+8)-5=2
Vitek1552 [10]

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(x + 8) - 5 = 2

+5

x + 8 = 7

- 8

x = -1

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8 0
3 years ago
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Y-2=-3(x+4)2 in standard form
Pavlova-9 [17]

Answer:

The standard for would be y = -3x^2 - 24x - 46

Step-by-step explanation:

To get this to standard form, start by squaring the parenthesis.

y - 2 = -3(x + 4)^2

y - 2 = -3(x^2 + 8x + 16)

Now distribute the -3

y - 2 = -3x^2 - 24x - 48

Now add the 2 to both sides

y = -3x^2 - 24x - 46

4 0
3 years ago
Question 2
Jlenok [28]

Answer:

x=6

Step-by-step explanation:

If b in in the middle of A and C then you would set AB equal to BC and solve

4 0
4 years ago
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A cereal box is 6.2 inches high, 8 inches long, and 2.5 inches wide. What is the volume
Gwar [14]

Answer:

124

Step-by-step explanation:

v = l×w×h

v = 6.2 × 8 × 2.5

v = 124

4 0
3 years ago
PLEASE GUYS HELP ITS DUE TONIGHT​
KATRIN_1 [288]

Answer:

20. AB = 42

21. BC = 28

22. AC = 70

23. BC = 20.4

24. FH = 48

25. DE = 10, EF = 10, DF = 20

Step-by-step explanation:

✍️Given:

AB = 2x + 7

BC = 28

AC = 4x,

20. Assuming B is between A and C, thus:

AB + BC = AC (Segment Addition Postulate)

2x + 7 + 28 = 4x (substitution)

Collect like terms

2x + 35 = 4x

35 = 4x - 2x

35 = 2x

Divide both side by 2

17.5 = x

AB = 2x + 7

Plug in the value of x

AB = 2(17.5) + 7 = 42

21. BC = 28 (given)

22. AC = 4x

Plug in the value of x

AC = 4(17.5) = 70

✍️Given:

AC = 35 and AB = 14.6.

Assuming B is between A and C, thus:

23. AB + BC = AC (Segment Addition Postulate)

14.6 + BC = 35 (Substitution)

Subtract 14.6 from each side

BC = 35 - 14.6

BC = 20.4

24. FH = 7x + 6

FG = 4x

GH = 24

FG + GH = FH (Segment Addition Postulate)

4x + 24 = 7x + 6 (substitution)

Collect like terms

4x - 7x = -24 + 6

-3x = - 18

Divide both sides by -3

x = 6

FH = 7x + 6

Plug in the value of x

FH = 7(6) + 6 = 48

25. DE = 5x, EF = 3x + 4

Given that E bisects DF, therefore,

DE = EF

5x = 3x + 4 (substitution)

Subtract 3x from each side

5x - 3x = 4

2x = 4

Divide both sides by 2

x = 2

DE = 5x

Plug in the value of x

DE = 5(2) = 10

EF = 3x + 4

Plug in the value of x

EF = 3(2) + 4 = 10

DF = DE + EF

DE = 10 + 10 (substitution)

DE = 20

4 0
3 years ago
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