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Korvikt [17]
2 years ago
12

I don"t remember how to do this, I just need where this negative fraction belong to.​

Mathematics
2 answers:
erastovalidia [21]2 years ago
8 0

Answer:

-3

Step-by-step explanation:

divide top by bottom

-18 / -6 = -3

which makes -18/6 have a whole number of -3

<3 Enjoy,

    Dea

Romashka [77]2 years ago
4 0

Awnser

-3

Step-by-step explanation:

because if you simplify -18/6 you get 3

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The line tangent to the graph of g(x) = x^{3}-4x+1 at the point (2, 1) is given by the formula
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well, about A and D, I just plugged the values on the slope formula of

\bf \begin{array}{llll} g(x)=x^3-4x+1\\ L(x) = 8(x-2)+1 \end{array} \qquad \begin{cases} x_1=1.9\\ x_2=2.1 \end{cases}\implies \cfrac{f(b)-f(a)}{b-a}

for A the values are 8.01 and 8.0, so indeed those "slopes" are close. \textit{\huge \checkmark}

for D the values are -2.25 and 8.0, so no dice on that one.

for B, let's check the y-intercept for g(x), by setting x = 0, we end up g(0) = 0³-4(0)+1, which gives us g(0) = 1.

checking L(x) y-intercept, well, L(x) is in slope-intercept form, thus the +1 sticking out on the far right is the y-intercept, so, dice. \textit{\huge \checkmark}

for C, well, the slope if L(x) is 8, since it's in slope-intercept form, the derivative of g(x) is g'(x) = 3x² - 4, and thus g'(0) = -4, so no dice.

for E, do they intercept at (2,1)?  well, come on now, L(x) is a tangent line to g(x), so that's a must for a tangent. \textit{\huge \checkmark}

for F, we know the slope of the line L(x) is 8, is g'(2) = 8?  let's check

recall that g'(x) = 3x² - 4, so g'(2) = 3(2)² - 4, meaning g'(2) = 8, so, dice. \textit{\huge \checkmark}

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Step-by-step explanation:

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The way to solve this is to do 5 1/5 divide by 2.5.
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3 years ago
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Andreas93 [3]

Answer:

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Step-by-step explanation:

You can use the center of a circle to write an equation in vertex form. Vertex form is (x-h)^2+(y-k)^2 = r^2 and the vertex is (h,k). Notice (h,k) are the opposite sign in the equation then as the point.

Here h = -4 and k = 3. Substitute these values and the value r = 5.

(x--4)^2 + (y-3)^2 = 5^2\\(x+4)^2 + (y-3)^2 = 25

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