Answer:
After 3 seconds while going up and 6 seconds while coming down
Step-by-step explanation:
Since projectile is launched from ground level with an initial velocity of v 0 feet per second, initial height =0
Height is given by
where v0 = initial velocity = 144
a) When h =288 ft.
At t= 3 or 6 seconds the projectile would be at height 288 ft.
So while going up after 3 seconds it wouldbe at a height of 288 ft and while coming after 6 seconds.
I can see it, it's too blurry and small
Answer:
Answer is a
Step-by-step explanation:
Y = -7
or
x = 10
or
y = x - 13
there can be endless answers
Answer:
<h3>9.9s</h3>
Step-by-step explanation:
First note that the river is on the ground level. The height of the river at the ground level is 0
Given the the height h above the river in feet of water going over the edge of the waterfall is modeled by h(t)=-16t^2+1552
When h = 0
0 = -16t^2+1552
16t^2 = 1552
t² = 1552/16
t² = 97
t = √97
<em>t = 9.9secs</em>
<em>Hence the time it takes is 9.9secs to the nearest tenth</em>
