Ask question

Ask question

All categories

3 years ago

10

PLEASEEE HELP!!! Which equations represent exponential growth?

1 answer:

Slav-nsk [51]3 years ago

6 0

Answer: all the choices where the thing inside the parenthesis is above 1 should be exponential growth the ones below 1 are decay

Step-by-step explanation: good luck lol

You might be interested in

nadya68 [22]

Answer: 1144

Step-by-step explanation:

Given: Machine A makes 7 parts every 10 minutes.

i.e. it makes $\dfrac{7}{10}$ parts in 1 minute.

Machine B makes 16 parts every 15 minutes.

i.e. it makes $\dfrac{16}{15}$ parts in 1 minute.

On Monday,

machine A makes parts for 12 hours(720 minutes). [1 hour = 60 minutes, 12 hours = 12 x 6 = 720 minutes]

i.e. Total parts made = $\dfrac{7}{10}\times720$

i.e. Total parts made = 504

machine B makes parts for 10 hours(=60x 10=600 minutes)

i.e. Total parts made = $\dfrac{16}{15}\times600$

i.e. Total parts made = 640

Total parts made by both machines = 504+640 =1144

Hence, the total number of parts made by the two machines on Monday=1144.

7 0

3 years ago

The zeros of function dare -3 and 8. Which expression could be a factor of function d?

erastovalidia [21]

Answer:

(x + 3)

Step-by-step explanation:

Using the zero product property

x-a = 0 x-b = 0 where a and b are the zeros

(x-a)(x-b) =0

(x- -3)(x -8) =0

(x+3) (x-8) =0

3 0

3 years ago

What is the probability of flipping a coin 4 times and it landing heads every time?

Anna71 [15]

1/4 times. Though there are only 2 sides within a coin, you are still give 4 chances.

:)

7 0

3 years ago

It’s all in the picture. WILL GIVE BRAINIEST TO CORRECT ANSWER

Nimfa-mama [501]

1. C
2. A
3. D
4. B

The 5 vertical lines shows the (left to right) minimum value, quartile 1, median, quartile 3, and maximum value.

8 0

3 years ago

PLEASE HELP I AM SO STUCK. IT IS DUE ~TOMORROW.

Flura [38]

Answer:

$A(\triangle ABC) = 7.2\: units^2$

Step-by-step explanation:

C = (0, 7)

Since, point A lies on y-axis, so it's x coordinate will be zero. Line y = 2x + 1 passes through point A.

Therefore, plug x = 0 in y = 2x +1, we find:

y = 2*0 + 1 = 0 + 1 = 1

Hence, coordinates of point A are (0, 1).

Now, by distance formula:

$AC= \sqrt{(0-0)^2 +(7-1)^2}$

$AC= \sqrt{(0)^2 +(6)^2 }$

$AC= \sqrt{0 +36 }$

$AC= \sqrt{36 }$

$AC= 6\: units$

Length of perpendicular CB dropped from point C (0, 7) to line y = 2x + 1 or 2x - y + 1 = 0 can be obtained as given below:

$CB =\frac{|2\times 0+(-1)\times 7+1|}{\sqrt {2^2 +(-1)^2} }$

$CB =\frac{|0-7+1|}{\sqrt {4 +1} }$

$CB =\frac{|-6|}{\sqrt {5} }$

$CB =\frac{6}{2.24}$

$CB =2.68\: units$

By Pythagoras Theorem:

$AB=\sqrt{AC^2 - CB^2}$

$AB=\sqrt{6^2 - (2.68)^2}$

$AB=\sqrt{36 - 7.18}$

$AB=\sqrt{28.82}$

$AB=5.36842621\: units$

$AB\approx 5.37\: units$

$A(\triangle ABC) = \frac{1}{2} \times AB\times CB$

$A(\triangle ABC) = \frac{1}{2} \times 5.37\times 2.68$

$A(\triangle ABC) = \frac{1}{2} \times 14.3916$

$A(\triangle ABC) = 7.1958$

$A(\triangle ABC) = 7.2\: units^2$

6 0

3 years ago