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Tomtit [17]
3 years ago
8

Given: ABCDis a parallelogram ∠GEC ≅ ∠HFA and AE ≅FC. Prove △GEC ≅ △HFA.

Mathematics
2 answers:
alexandr402 [8]3 years ago
7 0

See the proof in the image

OlgaM077 [116]3 years ago
4 0

<G E C=<H F A

A s

  • A E=F C
  • A F=E C

A lso

  • <CAH=<GCE

Hence

  • △GEC ≅ △HFA(ASA)
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An 8-sided fair die is rolled twice and the product of the two numbers obtained when the die is rolled two times is calculated.
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<u>Question Completion</u>

(b) Use the possibility diagram to calculate the probability that the product of the two numbers is

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v) Divisible by 4 or 6

Answer:

I) 0.125  (ii)0.828125   (iii)0.234375   (iv) 0.625   (v)0.65625

Step-by-step explanation:

The sample space for an 8-sided fair die rolled twice is:

[(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6),(1, 7),(1, 8)\\(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6),(2, 7),(2, 8)\\(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6),(3, 7),(3, 8)\\(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6),(4, 7),(4, 8)\\(5, 1), (5, 2), (5, 3), (5, 4), (5, 5),(5, 6),(5, 7),(5, 8)\\(6, 1), (6, 2), (6, 3), (6, 4)(6, 5),(6, 6),(6, 7),(6, 8)\\(7, 1), (7, 2), (7, 3), (7, 4)(7, 5),(7, 6),(7, 7),(7, 8)\\(8, 1), (8, 2), (8, 3), (8, 4)(8, 5),(8, 6),(8, 7),(8, 8)]\\

(a) The possibility diagram of the product of the two numbers appearing on the die in each throw

1, 2, 3, 4, 5, 6,7,8\\2, 4, 6, 8, 10, 12,14,16\\3,6,9,12,15,18,21,24\\4,8,12,16,20,24,28,32\\5,10,15,20,25,30,35,40\\6,12,18,24,30,36,42,48\\7,14,21,28,35,42,49,56\\8,16,24,32,40,48,56,64

(b)

I) A prime number

Number of Products which are prime numbers = 8 

P$(Product is a prime number)=\dfrac{8}{64}= \dfrac{1}{8}\\=0.125

ii) Not a perfect square  

Number of products which are perfect squares =11

 P$(Product is Not a perfect square)=\dfrac{64-11}{64}= \dfrac{53}{64}\\=0.828125

iii) A multiple of 5

Number of Products that are multiples of 5=15

P$(A multiple of 5)=\dfrac{15}{64}\\=0.234375

iv) Less than or equal to 21

Number of products less than or equal to 21=40

P$(Less than or equal to 21)=\dfrac{40}{64}=\dfrac{5}{8}\\=0.625

v) Divisible by 4 or 6

Products Divisible by 4 or 6= 42

P$(Divisible by 4 or 6)=\dfrac{42}{64}=\dfrac{21}{32}\\=0.65625

5 0
4 years ago
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