The answer is simply C.$2.50
Answer:
30/552
Step-by-step explanation:
In order to solve this problem you need to multiply the probability of getting grape for the first gumball with the probability of getting grape for the second gumball. Since there are 6 grape gumballs and a total of 24 gumballs (6*4). Then the probability of getting grape for the firs one is
![\frac{6}{24}](https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B24%7D)
Now there are only 5 grape gumballs available and one less in the total supply, therefore the probability of getting grape in the second try is
![\frac{5}{23}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B23%7D)
Finally we multiply them together to find the probability of getting two grapes in a row.
= ![\frac{30}{552}](https://tex.z-dn.net/?f=%5Cfrac%7B30%7D%7B552%7D)
First we must change these numbers to improper fractions:
![2\frac{4}{7}=\frac{18}{7}](https://tex.z-dn.net/?f=%202%5Cfrac%7B4%7D%7B7%7D%3D%5Cfrac%7B18%7D%7B7%7D%20)
![1\frac{3}{6}=\frac{9}{6}](https://tex.z-dn.net/?f=%201%5Cfrac%7B3%7D%7B6%7D%3D%5Cfrac%7B9%7D%7B6%7D%20)
So then we set it up:
÷ ![\frac{9}{6}](https://tex.z-dn.net/?f=%20%5Cfrac%7B9%7D%7B6%7D%20)
When we divide fractions like this, we must flip the second fraction and change the sign from division to multiplication like so:
![\frac{18}{7}*\frac{6}{9}](https://tex.z-dn.net/?f=%20%5Cfrac%7B18%7D%7B7%7D%2A%5Cfrac%7B6%7D%7B9%7D%20)
Then we solve:
![\frac{108}{63}](https://tex.z-dn.net/?f=%20%5Cfrac%7B108%7D%7B63%7D%20)
Then if we divide the numerator and the denominator by 9, we get:
or, in mixed-number form,
.
Answer:
5-4=1
Step-by-step explanation:
it would equal 1 since 4+1=5