<h3>3
Answers: Choice D, Choice E, Choice F</h3>
============================================================
Explanation:
The inequality 6x - 10y ≥ 9 solves to y ≤ (3/5)x - 9/10 when you isolate y.
Graph the line y = (3/5)x - 9/10 and make this a solid line. The boundary line is solid due to the "or equal to" as part of the inequality sign. We shade below the boundary line because of the "less than" after we isolated for y.
Now graph all of the points given as I've done so in the diagram below. The points in the blue shaded region, or on the boundary line, are part of the solution set. Those points are D, E and F.
We can verify this algebraically. For instance, if we weren't sure point E was a solution or not, we would plug the coordinates into the inequality to get...
6x - 10y ≥ 9
6(5) - 10(2) ≥ 9 .... plug in (x,y) = (5,2)
30 - 20 ≥ 9
10 ≥ 9 ... this is a true statement
Since we end up with a true statement, this verifies point E is one of the solutions. I'll let you check points D and F.
-----------
I'll show an example of something that doesn't work. Let's pick on point A.
We'll plug in (x,y) = (-1,1)
6x - 10y ≥ 9
6(-1) - 10(1) ≥ 9
-6 - 10 ≥ 9
-16 ≥ 9
The last inequality is false because -16 is smaller than 9. So this shows point A is not a solution. Choices B and C are non-solutions for similar reasons.
Use FOIL
28x² -8xy +7xy -2y²
28x² -xy -2y²
The answer is y=2x+5
To get it use point slope by taking two points and solving .
Slope formula
M= y2-y1/x2-x1
With two points
(0,5)(-5,-5)
M= -5-5/-5-0
M= -10/-5
M=2
2 is slope
Now get one of the points
(0,5) And slope to create equation y=mx+b . Now find b
5=2(0)+b
5=b
So now you can put it all together
Y= 2x+5
Answer:
hdjebejdbydvdfdvgdgbehdbdjgdjd
Answer:
First we need to calculate the are of each wall, since we alredy knew the length (l) and the width (w) which is the height of the wall in this case:
A = wl = 9 . 12 = 108 (ft²)
We also know that he painted 3 walls, we need to multiply our first result by 3, in other words, the area of wall that Brett painted is the sum of the area of three walls: 108 . 3 = 324 (ft²)