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choli [55]
3 years ago
6

Someone please help!​

Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
5 0

Answer:

10.

Step-by-step explanation:

Since 60 is the profit you need to make, you plug in 60 into P(x). So, you get the equation 60=0.3x^{2}+7x-40. The answer to this equation is 10. I think this is the correct answer.

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What expressions are equivalent to (a^2-16)(a+4)
Eddi Din [679]

Answer:

[(a)^2-(4^2)](a+4)

Step-by-step explanation:

7 0
3 years ago
A company manufactures 295 toy car each day. How many toy cars dose the company manufacture in 34 days?
exis [7]

295 X 34 = 10030 <== Cars in 34 days

3 0
3 years ago
Read 2 more answers
A strobe light is located at the center of a square dance room. the rotating light is 40 feet from each of the square walls and
Effectus [21]

The equation of the rotating light is an illustration of a secant function

The equation that represents the distance between the center of the circle and the light source is d(t) = 40\sec(\frac{\pi}{3}t)

<h3>How to determine the equation</h3>

The equation is a secant function represented by

y =A\sec(Bt)

Where:

A represents the amplitude

So, we have:

A = 40 --- the distance of the light from each square wall

B represents the period, and it is calculated as:

B = \frac{2\pi}{T}

The light completes its full rotation every 6 seconds.

This means that,

T = 6

So, we have:

B = \frac{2\pi}{6}

Simplify

B = \frac{\pi}{3}

Substitute values for A and B in y =A\sec(Bt)

y = 40\sec(\frac{\pi}{3}t)

Rewrite as a function

d(t) = 40\sec(\frac{\pi}{3}t)

Hence, the equation that represents the distance between the center of the circle and the light source is d(t) = 40\sec(\frac{\pi}{3}t)

Read more about trigonometry functions at:

brainly.com/question/1143565

5 0
2 years ago
Should i multiple 35×5 or48×28
natali 33 [55]
You should multiply 35•5
6 0
3 years ago
3x-4y=-5 y=4x-2 Is (1,2) a solution of the system?
Orlov [11]
If you want to check if (1,2) is a solution to the system, you have to plug the x and y values back into both equations. If they work for one equation, but not the other, than the coordinates are not a solution to the system.

3(1) - 4(2) = -5
3 - 8 = -5
-5 = -5 

2 = 4(1) - 2
2 = 4 - 2 
2 = 2

Since both of these checks are true, then (1,2) is a solution to the system.
7 0
3 years ago
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