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melamori03 [73]
3 years ago
14

Which of the following statements describes a correct method for solving this equation?4x+6=8x

Mathematics
1 answer:
nekit [7.7K]3 years ago
4 0
D.its the most logical answer
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Gradien garis -3x -2y = 7 adalah
Anuta_ua [19.1K]
Yo my bro the answer is 7621
3 0
3 years ago
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Here is the question in the image
Artist 52 [7]

The coordinates of the edges of the <em>mini-solar</em> cooker are (x₁, y₁) = (0, - 60) and (x₂, y₂) = (0, 60).

The distance between the two edges is 120 centimeters.

The equation for the <em>parabolic</em> mirror is x + 32 = (2/225) · y².

<h3>How to analyze a parabolical mini-solar cooker </h3>

Herein we must understand the geometry of the design of the <em>mini-solar</em> cooker to determine all needed information. The y-coordinates of the edges of the cooker are determined by Pythagorean theorem:

y = \pm \sqrt{(68\,cm)^{2}-(32\,cm)^{2}}

y = ± 60

The coordinates of the edges of the <em>mini-solar</em> cooker are (x₁, y₁) = (0, - 60) and (x₂, y₂) = (0, 60). The distance between the two edges is 120 centimeters.

Lastly, the equation of the <em>parabolic</em> mirror can be determined based on the equation of the parabola in <em>vertex</em> form:

x - h = C · (y - k)²     (1)

Where:

h, k - Coordinates of the vertex

C - Vertex constant

If we know that (h, k) = (- 32, 0) and (x, y) = (0, 60), then the vertex constant of the equation of the parabola is:

0 + 32 = C · 60²

C = 2/225

Then, the equation for the <em>parabolic</em> mirror is x + 32 = (2/225) · y².

To learn more on parabolae: brainly.com/question/21685473

#SPJ1

6 0
2 years ago
How do I find the volume of this sphere while using 3.14
yawa3891 [41]
Vsphere=(4/3)pir³

d/2=r
d=6.2
6.2/2=r=3.1

vsphere=(4/3)pi3.1³
vsphere=(4/3)pi29.791
Vsphere=124.72498666666666666666666666667
answer is 124.72498666666666666666666666667 cubic feet
or rounded to neares whole, 125 square feet
7 0
3 years ago
Evaluate the triple integral.
Irina-Kira [14]

The definition of the set E gives you a natural choice for the limits in the integral:

\displaystyle \iiint_E y \, dV = \int_0^6 \int_0^x \int_{x-y}^{x+y} y \, dz \, dy \, dx

Computing the integral, we get

\displaystyle \iiint_E y \, dV = \int_0^6 \int_0^x y ((x+y)-(x-y)) \, dy \, dx = 2 \int_0^6 \int_0^x y^2 \, dy \, dx

\displaystyle \iiint_E y \, dV = 2 \int_0^6 \frac13 (x^3 - 0^3) \, dx = \frac23 \int_0^6 x^3 \, dx

\displaystyle \iiint_E y \, dV = \frac23 \cdot \frac14 (6^4 - 0^4) = \boxed{216}

6 0
2 years ago
Select the correct answer.
fredd [130]

Stocks = 250

Net income = $4,000,000

Outstanding Shares = $1,000,000

Earnings Per Share = ?

Formula: EPS = Net Income / Outstanding Shares

Solution: EPS = Net Income / Outstanding Shares

= $4,000,000 / $1,000,000

= 4

Answer: Earnings Per Share = 4

3 0
3 years ago
Read 2 more answers
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