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2 years ago

Pls help me

Mathematics

1 answer:

Amanda [17]2 years ago

8 0

Answer:

the angle is 40°

Step-by-step explanation:

180 - 140 = 40

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Need help please stressing out over this problem!?!?!

ludmilkaskok [199]

$v = \frac{4}{3} \times \pi \times {r}^{3}$

Finding the radius,

$d = 2r, \: r = \frac{d}{2} = \frac{8}{2} = 4inches$

Plugging in our values,

$v = \frac{4}{3} \times 3.14 \times {4}^{3} = \frac{4}{3} \times 3.14 \times 64 = 267.95 {inches}^{3} \\$

Rounding to the nearest whol number,

$v = 268 {inches}^{3}$

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3 years ago

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Len [333]

Hope this helps a bit

8 0

2 years ago

Read 2 more answers

a rectangle shape whose length is 4 inches less than twice its width. the area is 30 square inches. whats the dimension

Ne4ueva [31]

Using the given information, we can say the following:
Width (W) = x
Length (L) = (2x - 4)
Area of Rectangle = L × W
Using this, we can formulate an equation for rectangle in question:
x(2x - 4) = 30
Expand and move everything to one side:
2x² - 4x - 30 = 0
Simplify by dividing everything on both sides by 2:
x² - 2x - 15 = 0
Factorise:
(x + 5)(x - 3) = 0
Set each factor equal to 0 and solve for x:
x + 5 = 0
x = -5 (a dimension cannot be negative so this is not the solution we want)
x - 3 = 0
x = 3 (this is the solution)
x = W = 3"
L = 2x - 4
L = 2(3) - 4
L = 2"

So, the length the rectangle is 2" and the width is 3"

5 0

3 years ago

In a process that manufactures bearings, 90% of the bearings meet a thickness specification. A shipment contains 500 bearings. A

vredina [299]

Answer:

c) P(270≤x≤280)=0.572

d) P(x=280)=0.091

Step-by-step explanation:

The population of bearings have a proportion p=0.90 of satisfactory thickness.

The shipments will be treated as random samples, of size n=500, taken out of the population of bearings.

As the sample size is big, we will model the amount of satisfactory bearings per shipment as a normally distributed variable (if the sample was small, a binomial distirbution would be more precise and appropiate).

The mean of this distribution will be:

$\mu_s=np=500*0.90=450$

The standard deviation will be:

$\sigma_s=\sqrt{np(1-p)}=\sqrt{500*0.90*0.10}=\sqrt{45}=6.7$

We can calculate the probability that a shipment is acceptable (at least 440 bearings meet the specification) calculating the z-score for X=440 and then the probability of this z-score:

$z=(x-\mu_s)/\sigma_s=(440-450)/6.7=-10/6.7=-1.49\\\\P(z>-1.49)=0.932$

Now, we have to create a new sampling distribution for the shipments. The size is n=300 and p=0.932.

The mean of this sampling distribution is:

$\mu=np=300*0.932=279.6$

The standard deviation will be:

$\sigma=\sqrt{np(1-p)}=\sqrt{300*0.932*0.068}=\sqrt{19}=4.36$

c) The probability that between 270 and 280 out of 300 shipments are acceptable can be calculated with the z-score and using the continuity factor, as this is modeled as a continuos variable:

$P(270\leq x\leq280)=P(269.5$

d) The probability that 280 out of 300 shipments are acceptable can be calculated using again the continuity factor correction:

$P(X=280)=P(279.5$

8 0

3 years ago

Write an equation for a rational function with:

hammer [34]

Answer:x= -3 {x=1 tx= -2 {x =1

Step-by-step explanation:

6 0

2 years ago