Answer:
Cylinder A: 603.508
Cylinder B: 602.88
Step-by-step explanation:
Cylinder A:
V=h
v=*5*3.14
V=38.44*5*3.14
V=192.2*3.14
V=603.508
Cylinder B:
V=h
V=*12*3.14
V=16*12*3.14
V=192*3.14
V=602.88
X/3- 2=6 find the value of x
2 answers:
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Answers:
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4.) A - </span><span>mean for April is higher than October's mean: mean in April is 67 and mean in October is 60
5.) A - </span><span>Neither data set has suspected outliers: meaning there's no data that is further apart from the group or set
6.) B - </span>There is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical
<span>
7.) C - </span>college spread is best described by the IQR. The high school spread is best described by the standard deviation: this is because of the wide range of data in the college than the data in the high school.
1.) C - Final exams: midterm = Q3 92 - Q1 80 = 12 and finals = Q3 85 - Q1 78 = 7, so finals exam has the smaller IQR.
2.) B - exam median is much higher than the class median: refer to the attached image of class and exam box and whisker graph
3.) A - <span>IQR is a better measure of spread for movies than it is for basketball games: because the data for movies are quite wide or apart from each other than the data in the basketball games
4.) A - </span><span>mean for April is higher than October's mean: mean in April is 67 and mean in October is 60
5.) A - </span><span>Neither data set has suspected outliers: meaning there's no data that is further apart from the group or set
6.) B - </span>There is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical
<span>
7.) C - </span>college spread is best described by the IQR. The high school spread is best described by the standard deviation: this is because of the wide range of data in the college than the data in the high school.