Givens
Petri Dish A sees a double ever 10 minutes
Petri Dish B sees a double ever 6 minutes
Consequences
A doubles 60 / 10 = 6 times.
B doubles 60 / 6 = 10 times.
Solution
If you work best with numbers then suppose there are 100 bacteria in both dishes at the beginning
A = 100 * 2^6
B = 100 * 2^10
A will have 100 * 64 = 6400 bacteria growing inside A
B will have 100 * 1024 = 102400 bacteria growing inside B
B/A = 102400 / 6400 = 16
There are 16 times as many in B than in A. <<<< Answer
Answer:
angle 1 = 105º
angle 2 = 75º
Step-by-step explanation:
angle 2 = 75º
corresponding angle to the 75º angle
angle 1 = 105º
it's supplementary to angle 2
180 - 75 = 105
<2,14> thats the answer its complicated but i got it after the 2nd try
The equation would be 2x+8=-48 and x=-28
Answer:
Part a) 
Part b) 
Part c) 
Part d) 
Step-by-step explanation:
see the attached figure to better understand the question
we know that
To find the length of the image after a dilation, multiply the length of the pre-image by the scale factor
Part a) we have
The scale factor is 5
The length of the pre-image is 3 cm
therefore
The length of the image AB after dilation is

Part b) we have
The scale factor is 3.7
The length of the pre-image is 3 cm
therefore
The length of the image AB after dilation is

Part c) we have
The scale factor is 1/5
The length of the pre-image is 3 cm
therefore
The length of the image AB after dilation is

Part d) we have
The scale factor is s
The length of the pre-image is 3 cm
therefore
The length of the image AB after dilation is
