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3 years ago

At first glance, we expect the Zeff of sodium (Z = 11) to be _, but in reality, it is closer to 2.667 because _.

1 answer:

6 0

This problem is asking for the theoretical effective nuclear charge for sodium and a reason behind its difference with the actual one. At the end, the answers are 1+ and because the 3s¹ electron has a small probability of being closer to the nucleus.

<h3>Effective nuclear charges</h3>

In chemistry, the effective nuclear charge is defined as the net positive charge valence electrons experience. In addition, one can approximate it with the equation:

Zeff = Z – S

Where Z is the atomic number or number of electrons and S the core electrons.

In such a way, since sodium has 11 electrons and 10 core electrons due to its electron configuration (1s²2s²2p⁶3s¹), one concludes its effective nuclear charge is:

Zeff = 11 - 10 = +1

On the other hand, since the actual effective nuclear charge has a value of about 2.667, one concludes this difference is due to the fact that the 3s¹ electron has a small tendency of being closer to the nucleus and therefore, there is a likelihood that this electron undergoes a greater attraction in comparison to the proposed in the theoretical model.

Learn more about effective nuclear charges: brainly.com/question/6965287

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the atomic number tells you the number of _______ in one atom of an element. It also tells you the number of ______ in a neutral

uysha [10]

Answer:

Protons, electrons, same in that order is the answer.

Explanation:

this has to do with the periodic table information.

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3 years ago

Using the bond energy data from your text (or the internet), determine (show calculations for) the approximate enthalpy change ,

aleksley [76]

Answer:

∆H= 438 KJ/mol

Explanation:

First, we have to find the energy bond values for each compound:

-) Cl-Cl = 243 KJ/mol

-) F-F = 159 KJ/mol

-) F-Cl = 193 KJ/mol

If we check the reaction we can calculate the number of bonds:

$Cl_2_(_g_)~+~3F_2_(_g_)~->~2ClF_3_(_g_)$

In total we will have:

-) Cl-Cl = 1

-) F-F = 3

-) F-Cl = 6

With this in mind. we can calculate the total energy for each bond:

-) Cl-Cl = (1*243 KJ/mol) = 243 KJ/mol

-) F-F = (3*159 KJ/mol) = 477 KJ/mol

-) F-Cl = (6*193 KJ/mol) = 1158 KJ/mol

Now, we can calculate the total energy of the products and the reagents:

Reagents = 243 KJ/mol + 477 KJ/mol = 720 KJ/mol

Products = 1158 KJ/mol

Finally, to calculate the total enthalpy change we have to do a subtraction between products and reagents:

∆H= 1158 KJ/mol-720 KJ/mol = 438 KJ/mol

I hope it helps!

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3 years ago

Write the chemical equation for the reaction whose enthalpy change is the standard enthalpy of formation of fructose, C6H12O6(s)

ziro4ka [17]

Answer:

$6 C(s) + 6_{H2}(g) + 3_{O2}(g)$

Explanation:

The chemical equation of the reaction is as follows

According to the question, data provided in the question is shown below:

$C_6H_12O_6$

The C = Carbon and its standard state is Graphite C(s)

The H = Hydrogen and its standard state is $H_2$ (s)

The O = Oxygen and its standard state is $O_2$ (s)

Now the chemical equation for the reaction is

$6 C(s) + 6_{H2}(g) + 3_{O2}(g)$

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4 years ago

What is the mass of each substance in the equation, after it is balanced

attashe74 [19]

Mass = mole x molar mass

Explanation:

The mole of the substance used in the bakanced eqn multipled by its molar mass equals to Its mass

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3 years ago

Scientists Pam and Alejandro were discussing a liquid found in the science lab that was missing it's label. In classifying the u

strojnjashka [21]

Your answer for this would be A. Mixtures cannot be separated by physical meansA pure substance is heterogeneous.

Hope This Helps :)

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3 years ago

Read 2 more answers

At first glance, we expect the Zeff of sodium (Z = 11) to be _____, but in reality, it is closer to 2.667 because _____.

At first glance, we expect the Zeff of sodium (Z = 11) to be _, but in reality, it is closer to 2.667 because _.