The enol carbon or ∝-carbon nucleophile attacks at molecular bromine in the acid-catalyzed α-bromination of a ketone
Treatment of ketones with bromine in the presence of acid will results in formation of a new C-Br bond at the alpha position. The purpose of the acid is to catalysed formation of the enol from ketone , which is active nucleophile in the reaction. This reaction is called haloform reaction which is used to identify the methyl substituted ketone in the presence of aldehyde.
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Answer:
Wide melting point range - impure sample with multiple compounds
Experimental melting point is close to literature value - pure sample of a single compound
Experimental melting point is below literature value - impure sample with multiple compounds
Narrow melting point range - pure sample of a single compound
Explanation:
The melting point of substances are easily obtainable from literature such as the CRC Handbook of Physics and Chemistry.
A single pure substance is always observed to melt within a narrow temperature range. This melting temperature is always very close to the melting point recorded in literature for the pure compound.
However, an impure sample with multiple compounds will melt over a wide temperature range. We also have to recall that impurities lower the melting point of a pure substance. Hence, the experimental melting point of an impure sample with multiple compounds is always below the literature value.
Answer:
its all of them ✨
Explanation:
i idk why there its all of them tho i promise you
Redox reactions are those <u>chemical reactions that involve the transfer of electrons between reactants</u>, altering the <em>oxidation state</em> of their elements.
In this type of reactions an element releases electrons that another element accepts, so there is a net transfer of charge.
When balancing redox reactions, not only must the chemical elements in the reactants and products be equalized (by the <em>law of conservation of the mass</em>), but also the charged that is transferred in the process must be balanced, since <u>the electrons that are lost in oxidation are the same as those that are gained in reduction (</u><em>law of conservation of charge:</em> <em>there is no destruction or net creation of electric charge</em>).
Answer:
6.63 M
Explanation:
NaCl(s) ---> Na^+(aq) + Cl^-(aq)
Given that [Na^+] = [Cl^-] = s
Where s= concentration of the both ions
Ksp = s^2
s= √Ksp
s= √43.9
s= 6.63 M
