the formula for density is p=m/v
m aka the mass = 5.4; the v aka the volume = 8
so, p=5.4/8
p= 0.675 g/cm^3
*let's just say the mass' unit is gram so the unit for the density is g/cm^3
Al species is oxidized in the reaction below al2o3(s) 3 co(g) → 2 al(s) 3 co2(g by oxidation
The reaction brought on by coming into touch with oxygen molecules is known as oxidation. These materials can be non-metals like live tissues or metals. Technically speaking, oxidation is the loss of one electron during the phase of interaction between two or more atoms.
Initially, the word "oxidation" was used to refer to chemical processes in which an element reacts with oxygen. An illustration of this is the oxidation of magnesium in the formation of magnesium oxide when magnesium metal and oxygen react.
The biological oxygen demand (BOD) of wastewater is decreased after oxidation, which also lessens some contaminants' toxicity. Some contaminants undergo this treatment and are transformed into carbon dioxide, water, and biosolids. Disinfection is commonly accomplished using chemical oxidation.
To learn more about oxidation please visit-
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No, the dilution does not change the number of moles dissolved
Explanation:
We can see that,
The molarity of the solution was 0.50 M
The volume of the solution is 10 ml.
No of moles of the solute was= volume * concentration
= 10 X 10^-3* 0.50
= 5*10^-3 moles
When the solution is diluted from 10 ml to 100ml, the molarity or concentration changes but number of moles remains constant.
The molarity of 100 ml solution will be
c=n/V
= 5*10^-3*/100*10^-3
= 0.05
when the solution is diluted to 100ml from 10 ml molarity changes from 0.5M TO 0.05 M
Answer:
(1) See below, (2) About 8.4 pH, (3) About 3.981 * 10⁻⁶ mol dm⁻³
Explanation:
1. A buffer is a solution that resist pH when adding a basic or acidic compound. It's purpose is to neutralize added acids and bases.
2. Remember that the formula for pH is -log [H+]. We have a 0.1 M solution of baking soda in water with [H+] of about 4.0 × 10⁻⁹. Therefore we can calculate the pH as follows...
pH = -log (4.0 × 10⁻⁹)
pH = -(-8.39794...) = (About) 8.4 pH of 0.1 M of baking soda
3. This question has a similar set up...
pH = -log [H+]
[H+] = inverse of log^- pH
[H+] = 10^-5.4 = (About) 3.981 
10⁻⁶
