Question

the length of a rectangle is thrice it's breadth. find the length and breadth if there perimeter is 88​

Answer 1

Given:

• The length of a rectangle is thrice it's breadth.
• Perimeter of rectangle = 88

$~$

To Find?

• Length and breadth

$~$

Using formula:

• Perimeter of rectangle = 2(L + B)

$~$

Let's assume:

• Length of rectangle = 3x
• Breadth of rectangle = x

$~$

$\sf \longmapsto 88 = 2(3x + x)$

$\sf \longmapsto 88 = 6x + 2x$

$\sf \longmapsto 88 = 8x$

$\sf \longmapsto x = \dfrac{88}{8}$

$\sf \longmapsto x = 11$

$~$

Hence,

• Length of rectangle = 3x = 33
• Breadth of rectangle = 11

Answer 2

Given :

• The length of a rectangle is thrice it's breadth.
• The perimeter of the rectangle is 88.

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To Find :

The Length and breadth of the rectangle.

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Solution :

We know that,

$\qquad{ \bold{ \pmb{2(Length + Breadth ) = Perimeter_{(rectangle)}}}}$

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Let's assume the breadth of the rectangle as x cm. Then the length will become 3x.

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Now, Substituting the given values in the formula :

$\qquad \dashrightarrow{ \sf{2(x + 3x )= 88}}$

$\qquad \dashrightarrow{ \sf{2(4x)= 88}}$

$\qquad \dashrightarrow{ \sf{8x= 88}}$

Dividing 8 by both sides :

$\qquad \dashrightarrow{ \sf{ \dfrac{8x}{8} = \dfrac{88}{8} }}$

$\qquad \dashrightarrow{ \bf{x= 11}}$

⠀

Therefore,

$\qquad { \pmb{ \bf{ Breadth _{(rectangle)} = 11}}}\:$

$\qquad { \pmb{ \bf{ Length _{(rectangle)} = 3 \times 11 \: = 33}}}\:$