3. Determine the intersection point(s) for the system.

Nadya [2.5K]

Simplifying 2x + 18y = 36 Solving 2x + 18y = 36 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-18y' to each side of the equation. 2x + 18y + -18y = 36 + -18y Combine like terms: 18y + -18y = 0 2x + 0 = 36 + -18y 2x = 36 + -18y Divide each side by '2'. x = 18 + -9y Simplifying x = 18 + -9y

3 0

2 years ago

At the start of the year, 15 chameleons were introduced into a zoo. The population of chameleons is expected to grow at a rate o

bearhunter [10]

Answer:

option-B

Step-by-step explanation:

We are given

At the start of the year, 15 chameleons were introduced into a zoo

so, $P_0=15$

The population of chameleons is expected to grow at a rate of 41.42% every year

so, r=0.4142

and x represents the number of years since the chameleons were introduced into the zoo

now, we can set equation to find total population

and we get

$P(x)=P_0(1+r)^x$

now, we can plug values

$P(x)=15(1+0.4142)^x$

$P(x)=15(1.4142)^x$

Average rate of change between 2 years and 4 years:

we can use formula

$A_1=\frac{P(4)-P(2)}{4-2}$

now, we can plug values

$A_1=\frac{15(1.4142)^{4}-15(1.4142)^{2}}{4-2}$

$A_1=14.99914$

Average rate of change between 4 years and 6 years:

we can use formula

$A_2=\frac{P(6)-P(4)}{6-4}$

now, we can plug values

$A_2=\frac{15(1.4142)^{6}-15(1.4142)^{4}}{6-4}$

$A_2=29.99770$

Average rate of change between 6 years and 8 years:

we can use formula

$A_3=\frac{P(8)-P(6)}{8-6}$

now, we can plug values

$A_3=\frac{15(1.4142)^{8}-15(1.4142)^{6}}{8-6}$

$A_3=59.99425$

now, we will check each options

option-A:

we can see that

$A_3-A_2=30$

So, this is FALSE

option-B:

$A_1=\frac{1}{2}A_2$

So, this is TRUE

option-C:

This is FALSE

option-D:

we got

$A_1=\frac{1}{2}A_2$

so, this is FALSE

5 0

2 years ago

Write the expression as a square of a monomial 121a^6

Nutka1998 [239]

The square root of 121 is 11. The square toot of a^6 is a^3. Therefore 121a^6 can be expressed as (11a^3)^2, and 11a^3 is a monomial since it is a single term with nothing added or subtracted to it or from it. So 121a^6 as a squared monomial is (11a^3)^2.

5 0

2 years ago

It takes a printer 6 hours to print the class schedules for all of the students in a college. A faster printer can do the job in

poizon [28]

The number of hours that it'll take both printers to do the job is 2.4 hours.

Number of hours used by printer A = 6 hours

Number of hours used by printer B = 4 hours

Therefore, the number of hours that'll be used by both printers will be calculated thus:

1/6x + 1/4x = 1

Using 12 as the LCM

2x + 3x = 12

5x = 12

Divide both side by 5

5x/5 = 12/5

x = 2.4 hours

Read related link on:

brainly.com/question/25115037

3 0

1 year ago

Problem solving to each question I need working out please take a picture of your working out thanks

4vir4ik [10]

I hope this helps you

5 0

2 years ago

3. Determine the intersection point(s) for the system.​

3. Determine the intersection point(s) for the system.