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hichkok12 [17]
3 years ago
8

Which function represents a parabola that is translated 2 units to the left and 6 units down from the parent function, f(x)=x^2

Mathematics
1 answer:
Luda [366]3 years ago
4 0

Translation involves moving a function along its coordinates

The image of the function is g(x) = (x + 2)^2 - 6

<h3>How to determine the new function</h3>

The parent function is given as:

f(x) = x^2

When the function is translated 2 units left, we have:

f'(x) = (x + 2)^2

When the function is translated 6 units down, we have:

f"(x) = (x + 2)^2 - 6

Rewrite as:

g(x) = (x + 2)^2 - 6

Hence, the image of the function is g(x) = (x + 2)^2 - 6

Read more about translation at:

brainly.com/question/11468584

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Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 139 millimeters,
FinnZ [79.3K]

Answer:

0.4010 = 40.10% probability that the sample mean would differ from the population mean by more than 0.8 millimeters

Step-by-step explanation:

To solve this question, we need to understan the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 139, \sigma = 6, n = 40, s = \frac{6}{\sqrt{40}} = 0.9487

Either the sample mean differs by 0.8 mm or less from the population mean, or it differs by more. The sum of these probabilities is decimal 1.

Probability it differs by less than 0.8mm

pvalue of Z when X = 139 + 0.8 = 139.8mm subtracted by the pvalue of Z when X = 139 - 0.8 = 138.2 mm

X = 139.8

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{139.8 - 139}{0.9487}

Z = 0.84

Z = 0.84 has a pvalue of 0.7995

X = 138.2

Z = \frac{X - \mu}{s}

Z = \frac{138.2 - 139}{0.9487}

Z = -0.84

Z = -0.84 has a pvalue of 0.2005

0.7995 - 0.2005 = 0.5990

What is the probability that the sample mean would differ from the population mean by more than 0.8 millimeters?

p + 0.5990 = 0.4010

0.4010 = 40.10% probability that the sample mean would differ from the population mean by more than 0.8 millimeters

7 0
3 years ago
Help me pleaseeee !!
ra1l [238]

Answer:

For x it would be 50 m2

Step-by-step explanation:

8 0
3 years ago
HELPPPP ASAP PLEASE!!!!
wlad13 [49]

Answer:

the answer is C

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Triangle ABC has a perimeter 22cm AB = 8cm BC =8cm By calculation, deduce whether triangle ABC is a right angle triangle. NEED A
Likurg_2 [28]

Answer:

No ABC is not a triangle

Step-by-step explanation:

Perimeter = 22 cm

AB = 8 cm ; BC = 8 cm

AC = 22 - ( 8 + 8 ) = 6 cm

But all those sides doesn't follow Pythagorean Theorem(AB^2 + BC^2 = AC^2) ....because 8^2 + 8^2 isn't equal to 6^2 ......

Had it followed the theorem , it could have been a right angle triangle...

6 0
3 years ago
Which expression is equal to 15x - 6
Keith_Richards [23]
15x-6=-90
explore how the values of algebraic expressions like100-x,5/x+5,and
 (3y) / (2y) change as the values of the variables change.
8 0
3 years ago
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