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Tatiana [17]
3 years ago
7

10. Lori plans to buy a book for $15.99, a magazine for $3.45, and a

Mathematics
2 answers:
kupik [55]3 years ago
6 0
Answer:

21 dollars I think
docker41 [41]3 years ago
5 0

Answer:

C

Step-by-step explanation:

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Need help asap thanks y'all
Vilka [71]

Answer:

what do you need help with?

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Pls helppp me this is very very urgent
Nat2105 [25]

Answer:

1. 5040

2. 20

Step-by-step explanation:

1. using the formula for permutation

nPr=n!/(n-r)!

10P4 = 10!/(10-4)!

=10*9*8*7*6!/6!

then we are left with

=10*9*8*7

=5040

2.using the formula for combination

nCr=n!/(n-r)!r!

6C3=6!/(6-3)!3!

=6*5*4*3!/3!3!

=6*5*4/3*2*1

=20

4 0
3 years ago
A certain radioactive isotope has a half-life of 15 days. If one is to make a table showing the half-life decay of a sample of t
Verdich [7]
A half-life of the isotope is 15 days and at start its mass is 32 g.
A table:
              t:                 m:
              0                32 g
             15               16 g
             30                 8 g
             45                 4 g
             60                 2 g
             75                 1 g
In the first column is used an arithmetic sequence ( a 1 = 0, d = 15 ).
In the second column is used a geometric sequence ( a 1 = 32, r = 1/2 )                       
7 0
3 years ago
Can someone solve what is n/n^3
emmasim [6.3K]

Answer:

Alex = No B.

Step-by-step explanation:

1) Use Quotient Rule: \frac{x^{a} }{x^{b} } =x^{a-b}

n^{1-3}

2) Simplify 1 - 3 = 2

n^{-2}

3) Use Negative Power Rule: x^{-a} =\frac{1}{x^{a} }

\frac{1}{n^{2} }

3 0
2 years ago
The table below shows the number of cameras made when an assembly line runs at a constant rate for a certain number of hours. Nu
jeka57 [31]

Computing the rate we get:

\frac{300}{10}\frac{cameras}{\text{hour}}=30\frac{cameras}{\text{hour}}

Then, when the assembly line runs at the same rate for 24 hours they will produce:

24\text{hour}\cdot30\frac{cameras}{\text{hour}}=720\text{ cameras}

Answer: Option C) 720.

7 0
1 year ago
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