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uranmaximum [27]
2 years ago
11

Find a rational number and an irrational number that are between 5.2 and 5.5. Include the decimal approximation of the irrationa

l number to the nearest hundredth
Mathematics
1 answer:
mote1985 [20]2 years ago
3 0

Answer:

5.3

Step-by-step explanation:

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A funnel is made up of a partial cone and a cylinder as shown in the figure. The maximum amount of liquid that can be in the fun
julsineya [31]
The answer is 15.75_ cm3
6 0
3 years ago
Read 2 more answers
Anyone i need help with this
DIA [1.3K]

Answer:

Step-by-step explanation:

a1=90-a2

a1=90-30=60

a2 is opposite 30 and opposite angles are equal so

a2=30

The sum of the angles of a triangle are equal to 180 degrees.

a2+a3+70=180

a3+30+70=180

a3=100=180

a3=80

4 0
3 years ago
Please I need help asap!!
Solnce55 [7]

Answer:

B

Step-by-step explanation:

Hi there!

We're given the measure of <AOC (the big angle) as 90°

and the measure of <BOC as 14° and the measure of <AOB as (3x+46)°

we want to find the value of what x is

because of angle addition postulate, m<AOC=m<BOC+m<AOB

so we can substitute our known values into that equation

90°=14°+3x°+46°

our goal is to isolate the variable of x onto one side

add 14 and 46 together

90°=3x°+60°

subtract 60° from both sides

30°=3x°

divide both sides by 3

10°=x

therefore B is your answer

Hope this helps!

7 0
3 years ago
a. Fill in the midpoint of each class in the column provided. b. Enter the midpoints in L1 and the frequencies in L2, and use 1-
Tresset [83]

Answer:

\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1}  & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7}  & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}

Using the frequency distribution, I found the mean height to be 70.2903 with a standard deviation of 3.5795

Step-by-step explanation:

Given

See attachment for class

Solving (a): Fill the midpoint of each class.

Midpoint (M) is calculated as:

M = \frac{1}{2}(Lower + Upper)

Where

Lower \to Lower class interval

Upper \to Upper class interval

So, we have:

Class 63-65:

M = \frac{1}{2}(63 + 65) = 64

Class 66 - 68:

M = \frac{1}{2}(66 + 68) = 67

When the computation is completed, the frequency distribution will be:

\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1}  & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7}  & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}

Solving (b): Mean and standard deviation using 1-VarStats

Using 1-VarStats, the solution is:

\bar x = 70.2903

\sigma = 3.5795

<em>See attachment for result of 1-VarStats</em>

8 0
3 years ago
I need with the volume!!!
murzikaleks [220]

Answer:

Tim read 81 pages.

Step-by-step explanation:

If he read 3 pages on Monday and tripled the amount of pages he red based of off the amount of pages he read the previous day, he would have read 3 pages on Monday, 9 pages on Tuesday, 27 pages on Wednesday, and 81 pages on Thursday.

Monday: 3

Tuesday: 3 x 3 = 9

Wednesday: 9 x 3 = 27

Thursday: 27 x 3 = 81

I hope this helps you! :D

8 0
3 years ago
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