Answer:
(i) 1/6
(ii) 1/6
(iii) 4/6 = 2/3
(iv) 3/6 = 1/2
(v) 3/6 = 1/2
(vi) 0/6 = 0
Answer:
1
Step-by-step explanation:
The answer is <span>012.96. Hope this helps!
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Let's take the derivative of each term one by 1
x^2
Apply the power rule for derivatives.
2x^(2-1) = 2x
You get 2x.
2x
Apply the power rule (x^1) and the constant multiple rule.
2 * x^(1-1) = 2 * x^0 = 2
You get 2.
-4
The derivative of a constant is 0.
Put that together and you get 2x + 2
Have an awesome day! :)
Answer:
D.
Step-by-step explanation:
To tell whether the domains can include 0, all you need to do is find where x = 0, and whether the y-value is real.
h(x) = sqrt(2x^2 + 5x - 3)
= sqrt(0^2 + 5 * 0 - 3)
= sqrt(-3)
Since this includes the square root of a negative number, h(0) is an imaginary number. That means that we can eliminate choices A and B.
If you look at the graph of w(x), when x = 0, there is a real value for the y-value on the graph. But, if you think about it, if you have 0 workers, there is no way that you can still be producing wrenches. So, the domain cannot contain 0.
Your answer will be D.
Hope this helps!!
