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irina1246 [14]
2 years ago
14

I do not know how to do this please help​

Mathematics
1 answer:
zhenek [66]2 years ago
4 0
Use this app take a picture of it
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How do I find this answer ?
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This means that for a given year that Indiana became a state, Arizona became a state 96 years later. The expression (b) y+96=1896 is correct.
4 0
3 years ago
Line FG goes through the points (4,9) and (1,3). Which equation represents a line that is perpendicular to FG and passes through
stiks02 [169]

Answer:

x + 2y= 2

Step-by-step explanation:

Given

Points:

F = (4,9)

G = (1,3)

Required

Determine the equation of line that is perpendicular to the given points and that pass through (2,0)

First, we need to determine the slope, m of FG

m = \frac{y_2 - y_1}{x_2 - x_1}

Where

F = (4,9) --- (x_1,y_1)

G = (1,3) --- (x_2,y_2)

m = \frac{3 - 9}{1 - 4}

m = \frac{- 6}{- 3}

m =2

The question says the line is perpendicular to FG.

Next, we determine the slope (m2) of the perpendicular line using:

m_2 = -\frac{1}{m}

m_2 = -\frac{1}{2}

The equation of the line is then calculated as:

y - y_1 = m_2(x - x_1)

Where

m_2 = -\frac{1}{2}

(x_1,y_1) = (2,0)

y - 0 = -\frac{1}{2}(x - 2)

y  = -\frac{1}{2}(x - 2)

y  = -\frac{1}{2}x + 1

Multiply through by 2

2y = -x + 2

Add x to both sides

x + 2y= -x +x+ 2

x + 2y= 2

Hence, the line of the equation is x + 2y= 2

8 0
3 years ago
Read 2 more answers
Would appreciate some help with this:<br><br> Verify (sinq+cosq)^2 - 1 = sin2q
Phantasy [73]

Hello from MrBillDoesMath!

Answer:

See Discussion below

Discussion:

(sinq + cosq)^2 =                                     => (a +b)^2 = a^2 + 2ab + b^2

(sinq)^2 + (cosq)^2 + 2 sinq* cosq        => as (sinx)^2 + (cosx)^2 = 1

1 + 2 sinq*cosq              (*)


Setting a = b = q in the trig identity:

sin(a+b) = sina*cosb + cosa*sinb                      

sin(2q) =                      (**)

sinq*cosq + cosq*sinq      => as both terms are identical

2 sinq*cosq


Combining (*) and (**)

(sinq + cosq)^2 = 1 + 2sinq*cosq     => (**) 2sinq*cosq =  sqin(2q)

                          = 1 +  sin(2q)

Hence

(sinq + cosq)^2  = 1 +  sin(2q)            => subtracting 1 from both sides

(sinq + cosq)^2  - 1 =   sin(2q)  

The last statement is what we are trying to prove.



Thank you,

MrB

7 0
3 years ago
Simplify the expression (m^3)^-1 (x^2)^5
Katyanochek1 [597]
(m^3)^-1 (x^2)^5 = (m^-3) (x^10) = x^10 / m^3
6 0
3 years ago
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