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lana [24]
2 years ago
6

Anne fires a toy rocket into the air from the top of a barn. The height of the rocket above the ground in feet after t seconds i

s given by
the function h(t) = -5t^2 + 20t -15. After completing the trajectory, Anne finds that the maximum height the toy rocket reached in the
air is represented by the expression -5(t-__)^2+5 Write the missing piece of the expression
Mathematics
1 answer:
astra-53 [7]2 years ago
5 0

The missing piece of the expression is 2

<h3>Maximum height of the rocket</h3>

From the question, the height of the rocket above the ground in feet after t seconds is given by the function h(t) = -5t^2 + 20t -15

At maximum height, the velocity of the function is zero. Hence;

dh/dt - -5(2)t + 20
dh/dt = -10t + 20

Write the expression in vertex form as shown:

h(t) = -5t^2 + 20t -15

h(t) = -5(t^2 - 4t +3)

h(t) = -5(t^2 - 4t + 2^2 + 3 - 2^2)

h(t) = -5((t+2)^2 +5
h(t) = -5((t+2)^2 + 11

Hence the missing piece of the expression is 2

Learn more on vertex form here: brainly.com/question/525947

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sergiy2304 [10]
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8-5
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the answer should be 3 after plugging in the variables.

3 0
3 years ago
What is the rate of change?
slega [8]

Answer:

X= -1. Y=-5

Step-by-step explanation:

The x decreases by -1 and the y decreases by -5 .

3 0
3 years ago
What is the simplified form of 0.2 to the fifth power?
Tanya [424]

Answer:

0.32

Step-by-step explanation:

0.2 to the fifth power is 0.00032, so that simplified is 0.32.

3 0
3 years ago
Read 2 more answers
Can someone plz help me with this!
asambeis [7]

Answer:

(arranged from top to bottom)

System #3, where x=6

System #1, where x=4

System #7, where x=3

System #5, where x=2

System #2, where x=1

Step-by-step explanation:

System #1: x=4

2x+y=10\\x-3y=-2

To solve, start by isolating your first equation for y.

2x+y=10\\y=-2x+10

Now, plug this value of y into your second equation.

x-3(-2x+10)=-2\\x+6x-30=-2\\7x=28\\x=4

System #2: x=1

x+2y=5\\2x+y=4

Isolate your second equation for y.

2x+y=4\\y=-2x+4

Plug this value of y into your first equation.

x+2(-2x+4)=5\\x+(-4x)+8=5\\x-4x+8=5\\-3x=-3\\x=1

System #3: x=6

5x+y=33\\x=18-4y

Isolate your first equation for y.

5x+y=33\\y=-5x+33

Plug this value of y into your second equation.

x=18-4(-5x+33)\\x=18+20x-132\\-19x=-114\\x=6

System #4: all real numbers (not included in your diagram)

y=13-2x\\8x+4y=52

Plug your value of y into your second equation.

8x+4(13-2x)=52\\8x+52-8x=52\\0=0

<em>all real numbers are solutions</em>

System #5: x=2

x+3y=5\\6x-y=11

Isolate your second equation for y.

6x-y=11\\-y=-6x+11\\y=6x-11

Plug in your value of y to your first equation.

x+3(6x-11)=5\\x+18x-33=5\\19x=38\\x=2

System #6: no solution (not included in your diagram)

2x+y=10\\-6x-3y=-2

Isolate your first equation for y.

2x+y=10\\y=-2x+10

Plug your value of y into your second equation.

-6x-3(-2x+10)=-2\\-6x+6x-30=-2\\-30=-2

<em>no solution</em>

System #7: x=3

y=10+x\\2x+3y=45

Plug your value of y into your second equation.

2x+3(10+x)=45\\2x+30+3x=45\\5x=15\\x=3

3 0
3 years ago
Find the difference between (2x-5) and (3-9x)
BARSIC [14]
I think it might be 11x-8
I'm really sorry if that's wrong
4 0
3 years ago
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