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NikAS [45]
2 years ago
8

Evaluate f(x)=x+6 when x=-2,0, and 5 . f(-2)= f(0)= f(5)=

Mathematics
1 answer:
rosijanka [135]2 years ago
8 0

Answer:

The solution is below

Step-by-step explanation:

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Use the formula
natita [175]
A=bh
108=<span>12*h
9in=h
The height is 9 inches.</span>
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3 years ago
Timed!!! few mins left HELP!
LUCKY_DIMON [66]

Answer:

2x - 15

3a + 17

1000/y

Step-by-step explanation:

1.

15 less means subtract 15

twice a number is 2x

Answer: 2x - 15

2.

increased by 17 means add 17

3 times a number is 3a

Answer: 3a + 17

3.

1000 divided by y number of employees

Answer: 1000/y

7 0
3 years ago
I know how to do this but I just want to spend some points :)
Lunna [17]

Answer:

domain: all real numbers

range: y<-2

Step-by-step explanation:

I think its correct but already know the answer sooo yea

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3 years ago
Solve: 2|x+7|-4 is less than or equal to 0
Yuri [45]

Answer:

less than

Step-by-step explanation:

5 0
4 years ago
Suppose 88% of all batteries from a supplier have acceptable voltages. A certain type of flashlight requires two D batteries, an
ira [324]

Answer:

0.3036 = 30.36% probability that at least 9 of the flashlights function properly.

Step-by-step explanation:

For each flashlight, there are only two possible outcomes. Either it works, or it does not. Flashlights are independent. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Flashlight works correctly if both its batteries have acceptable voltages:

Each battery has an 88% = 0.88 probability of working correctly(having acceptable voltage), so the probability of the flashlight working correctly is given by:

p = (0.88)^2 = 0.7744

10 flashlights.

This means that n = 10

What is the probability that at least 9 of the flashlights function properly?

This is

P(X \geq 9) = P(X = 9) + P(X = 10)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 9) = C_{10,9}(0.7744)^{9}.(0.2256)^{1} = 0.2260

P(X = 10) = C_{10,10}(0.7744)^{10}.(0.2256)^{0} = 0.0776

P(X \geq 9) = P(X = 9) + P(X = 10) = 0.2260 + 0.0776 = 0.3036

0.3036 = 30.36% probability that at least 9 of the flashlights function properly.

6 0
3 years ago
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