A trapezoid has a set of parallel bases with lengths 3 inches and 5 inches and a helght of 8 inches. What is the area

Mathematics

1 answer:

Aleks04 [339]2 years ago

7 0

Answer:

The area of trapezoid is 32 inches^2

Step-by-step explanation:

Parallel base 1 = a = 3 inches

Parallel base 2 = b = 5 inches

Height of trapezoid = 8 inches

We need to find area of trapezoid

The formula used is: $Area\:of\:trapezoid=\frac{a+b}{2}\times h$

Now putting the values and finding area of trapezoid

$Area\:of\:trapezoid=\frac{a+b}{2}\times h\\Area\:of\:trapezoid=\frac{5+3}{2}\times 8\\Area\:of\:trapezoid=\frac{8}{2}\times 8\\Area\:of\:trapezoid=4\times 8\\Area\:of\:trapezoid=32$

So, the area of trapezoid is 32 inches^2

You might be interested in

Order the following expressions from least to greatest<br><br> (Quick Please)

ivann1987 [24]

Square root (3) < square root (pie) < 2

6 0

1 year ago

Suzanne dropped her penny jar.she found some of the pennies, but some are still missing.she found 6/10 of the pennies on the rug

Rom4ik [11]

1/10 of the pennies are still missing

5 0

3 years ago

Read 2 more answers

Help me. I don't understand. Please help me find X and IK

sertanlavr [38]

Answer:

$x=4\\\\y=6\\\\IK=47$

Step-by-step explanation:

Two Tangent Theorem: Tangents which meet at same point are equal in length.

Here tangents at J and H meet at I.

$Hence\ HI=IJ\\\\y^2-10=4y+2\\\\y^2-4y-12=0\\\\y^2-6y+2y-12=0\\\\y(y-6)+2(y-6)=0\\\\(y-6)(y+2)\\\\y\ can\ not\ be\ negative\ as\ in\ that\ case\ IJ\ will\ be\ negative.\\\\Hence\ y=6\\\\IJ=4y+2=4\times 6+2=26\\\\\\\\Tangents\ at\ J\ and\ L\ meet\ at\ K.\ Use\ two\ tangent\ theorem.\\\\JK=KL\\\\5x+1=6x-3\\\\6x-5x=1+3\\\\x=4\\\\JK=5x+1=5\times 4+1=21\\\\\\IK=IJ+JK=26+21\\\\IK=47$