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just olya [345]
3 years ago
5

Which expression is equivalent to the given expression? Assume the denominator does not equal zero.

Mathematics
1 answer:
DENIUS [597]3 years ago
7 0

ok so basically i got =2rx8y9

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A sphere is not a polyhedron true or false?
lesya [120]

it is false because a sphere is basically a three- dimensional circle. It is a polyhedron.

7 0
3 years ago
Multi step equation -3x-2=-1
Shkiper50 [21]

x = -1/3

Explanation:

-3x-2=-1

collect like terms by adding +2 to both sides:

-3x -2 + 2 = -1 + 2

-3x = 1

Divide both sides by the coefficient of x:

coefficient of x = -3

-3x/-3 = 1/-3

x = -1/3

8 0
1 year ago
Please help. The correct and best answer gets brainiest! 29 points!!
attashe74 [19]

Answer:(15, 100)

Step-by-step explanation:

first find the coordinates of the point above (3, 20)

you just look at the x axis and where the point is in this case x would be 6 and then you find y which would be 40

so the coordinate would be (6, 40)

now subtract (6, 40) by (3, 20)

6-3= 3

40- 20= 20

you get the first coordnites which is what you add (12,80) to

12 +3= 15

80+ 20= 100

you get the coordinates (15, 100)

4 0
3 years ago
Which set is closed under the operation multiplication?
oee [108]
I have another set of choices here:

A. {0.5, 1, 2} 


B. {1, 2, 4} 


C. {1, 2, 3, 4, 5} 


<span>D. {0} 
</span>
If you multiply two numbers from a closed set the answer is in the set. 
<span>So A is not closed because 2 x 2 = 4 which isn't in the set. Only 0.5, 1, and 2 are in set A. </span>

<span>Try multiplying the largest numbers in sets B, C, and D by themselves. You will soon discover the closed set.</span>
3 0
3 years ago
Remember to show work and explain. Use the math font.
vichka [17]

Answer:

\large\boxed{1.\ f^{-1}(x)=\sqrt[12]{3^x}}\\\\\boxed{2.\ f^{-1}(x)=\sqrt[4]{3^x}}\\\\\ \boxed{3.\ f^{-1}(x)=\sqrt[3]{4^{7-x}}}

Step-by-step explanation:

(a^n)^m=a^{nm}\\\\\log_ab=c\iff a^c=b\\\\a^{\log_ax}=x\\\\n\log_ab=\log_ab^n\\\\\log_ab+\log_ac=\log_a(bc)\\============================\\\\1.\\y=3\log_3x^4\to y=\log_3(x^4)^3\to y=\log_3x^{12}

2.\\y=\log_3x^4\\\\\text{Exchange x and y. Solve for y:}\\\\\log_3y^4=x\Rightarrow3^{\log_3y^4}=3^x\Rightarrow y^{4}=3^x\\\\y=\sqrt[4]{3^x}\\-------------------------

3.\\y=-\log_4x^3+7\\\\\text{Exchange x and y. Solve for y:}\\\\-\log_4y^3+7=x\qquad\text{subtract 7 from both sides}\\\\-\log_4 y^3=x-7\qquad\text{change the signs}\\\\\log_4y^3=7-x\Rightarrow4^{\log_4y^3}=4^{7-x}\\\\y^3=4^{7-x}\Rightarrow y=\sqrt[3]{4^{7-x}}

7 0
3 years ago
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