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DerKrebs [107]
2 years ago
11

A line passes through the points (3,14) and (7,18) Write a linear function rule in terms of x and y for this line, Help! I might

not be going to my school anymore if I don't pass my math classes :(
Mathematics
2 answers:
4vir4ik [10]2 years ago
7 0
SOLUTION: The slope-intercept form of a line is y = mx + b, where m is the slope, and b is the y-intercept.
Step 1: Find the slope The slope of the line through two points (x1,y1) and (x2,y2) can be found by using the formula below. ...
Step 2: Find the y-intercept (b) ...
Step 3: Write the equation in slope-intercept form (y = mx + b) ...
Step 4: Check Your Equation.

Does this make sense?
MrRissso [65]2 years ago
3 0

Answer:

y=1x+11

Step-by-step explanation:

1. Find the slope of the given points

\frac{y2-y1}{x2-x1}

\frac{18-14}{7-3} =\frac{4}{4} =1

2. Pick any point to find the y-intercept

(3, 14)

x=3, y=14, m=1

3. Substitute

y=mx+b

14=1(3)+b

14=3+b

14-3=b

11=b

4. Write the linear function rule

y=mx+b

y=1x+11

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Give three points that lie on a line with a<br>slope of -2/5​
Luda [366]

Answer:

The three points that lie on a line y = -2/5x with a slope -2/5 will be:

  • (0, 0)
  • (5, -2)
  • (10, -4)

Please check the attached graph also.

Step-by-step explanation:

We know that the slope-intercept form of the line equation is

y = mx+b

where m is the slope and b is the y-intercept

Given

slope = m = -2/5

We suppose the line passes through the origin.

so b = 0

substituting m = -2/5 and b = 0 in the slope-intercept form

y = mx+b

y = -2/5x + 0

y = -2/5x

Thus, the equation of line with the slope m = -2/5 and passes through the origin (0, 0) will be:

y = -2/5x

As the equation of line passes through (0, 0), thus the point (0, 0) lies on the line.

Putting x = 0 in the equation y = -2/5x

y = -2/5 × (0)

y = 0

Thus, (0, 0) is the point which also passes through the line

Putting x = 5 in the equation y = -2/5x

y = -2/5 × 5

y = -2

Thus, (5, -2) is the point which also passes through the line

Now, putting x = 10 in the equation y = -2/5x

y = -2/5 × 10

y = -4

Thus, (10, -4) is the point which also passes through the line.

Thus, the three points that lie on a line y = -2/5x with a slope -2/5 will be:

  • (0, 0)
  • (5, -2)
  • (10, -4)

Please check the attached graph also.

5 0
3 years ago
F(x)=log5 (2x+12)+2 yeah this ome threw me off
sergeinik [125]

Answer:

See below for a graph

Step-by-step explanation:

Let's call the parent function g(x) = log₅(x), which has a vertical asymptote at x=0, and goes through the points (1, 0), (5, 1), (25, 2).

Then this function is

... f(x) = g(2(x+6)) +2

That is, the function is horizontally compressed by a factor of 2, shifted left 6 units, and shifted up 2 units. This moves the points listed above to ...

... (-5.5, 2), (-3.5, 3), (6.5, 4)

The graph shows the parent function and the listed points in blue, then the transformed function and the corresponding points in red.

5 0
3 years ago
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olga nikolaevna [1]
The answer the your question should be a slope of -3
6 0
4 years ago
Solve for S.<br> 4s-28=4
lina2011 [118]

Answer: s = 8

Step-by-step explanation:

5 0
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kherson [118]

Answer:     Ogro that is 2727

Step-by-step explanation:

6 0
3 years ago
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