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2 years ago

Find the volumeeeeeeee

Mathematics

1 answer:

Alla [95]2 years ago

6 0

Answer:

264 yd³

Step-by-step explanation:

The volume of a triangular pyramid can be found using the formula ...

V = 1/2LWH

where H is the height of the triangular base.

V = 1/2(8 yd)(11 yd)(6 yd)

V = 264 yd³ . . . . volume of the prism

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The diagonals of an isosceles trapezoid are represented by x+10 and 2x+5.what is the value of x?

DanielleElmas [232]

Answer:

x=5

Step-by-step explanation:

since it’s isosceles trapezoid, diagonals are equal.

x+10=2x+5

x=5

4 0

3 years ago

A rectangular parking lot must have a perimeter of 440 feet and an area of at least 8000 square feet. Describe the possible leng

tangare [24]

Answer:

The possible parking lengths are 45.96 feet and 174.031 feet

Step-by-step explanation:

Let x be the length of rectangular plot and y be the breadth of rectangular plot

A rectangular parking lot must have a perimeter of 440 feet

Perimeter of rectangular plot =2(l+b)=2(x+y)=440

2(x+y)=440

x+y=220

y=220-x

We are also given that an area of at least 8000 square feet.

So, $xy \leq 8000$

So, $x(220-x) \leq 8000$

$220x-x^2 \leq 8000$

So, $220x-x^2 = 8000\\-x^2+220x-8000=0$

General quadratic equation : $ax^2+bx+c=0$

Formula : $x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

$x=\frac{-220 \pm \sqrt{220^2-4(-1)(-8000)}}{2(-1)}\\x=\frac{-220 + \sqrt{220^2-4(-1)(-8000)}}{2(-1)} , \frac{-220 - \sqrt{220^2-4(-1)(-8000)}}{2(-1)}\\x=45.96,174.031$

So, The possible parking lengths are 45.96 feet and 174.031 feet

3 0

3 years ago

(Which is the simplified form of the expression ? 3(7/5x+4)-2(3/2-5/4x)

Illusion [34]

Answer:

let's see what to do buddy....

Step-by-step explanation:

$3( \frac{7}{5}x + 4) - 2( \frac{3}{2} - \frac{5}{4}x) \\ \\ = \frac{21}{5}x + 12 - 3 + \frac{5}{2}x \\ \\ = \frac{(21 \times 2) + (5 \times 5)}{10} x + 9 = \\ \\ \frac{42 + 25}{10} x + 9 = \frac{67}{10}x + 9 = 6.7x + 9$

5 0

3 years ago

?????????????????????????

diamong [38]

Answer:

There are 0.00003 km in 3 cm

(Only 4 zeros after the decimal place)

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

I own a large truck, and my neighbor owns four small trucks that are all identical. My truck can carry a load of at least $600$

erastova [34]

Answer:

there is no greatest load

Step-by-step explanation:

Let x and y represent the load capacities of my truck and my neighbor's truck, respectively. We are given two relations:

x ≥ y +600 . . . . . my truck can carry at least 600 pounds more

x ≤ (1/3)(4y) . . . . . my truck carries no more than all 4 of hers

Combining these two inequalities, we have ...

4/3y ≥ x ≥ y +600

1/3y ≥ 600 . . . . . . . subtract y

y ≥ 1800 . . . . . . . . multiply by 3

My truck's capacity is greater than 1800 +600 = 2400 pounds. This is a lower limit. The question asks for an <em>upper limit</em>. The given conditions do not place any upper limit on truck capacity.

4 0

3 years ago

Read 2 more answers