Answer:
We must must transform the standard form equation 3x+6y=5 into a slope-intercept form equation (y=mx+b) to find its slope.
3x+6y=5 (Subtract 3x on both sides.)
6y=−3x+5 (Divide both sides by 6.)
y=−
6
3
x+
6
5
y=−
2
1
x+
6
5
The slope of our first line is equal to −
2
1
. Perpendicular lines have negative reciprocal slopes, so if the slope of one is x, the slope of the other is −
x
1
.
The negative reciprocal of −
2
1
is equal to 2, therefore 2 is the slope of our line.
Since the equation of line passing through the point (1,3), therefore substitute the given point in the equation y=2x+b:
3=(2×1)+b
3=2+b
b=3−2=1
Substitute this value for b in the equation y=2x+b:
y=2x+1
Hence, the equation of the line is y=2x+1.
Step-by-step explanation:
Answer:
Domain- Interval Notation:
(
−
∞
,
∞
)
Set-Builder Notation:
{
x
|
x
∈
R
}
Range- Interval Notation:
(
−
9
,
∞
)
Set-Builder Notation:
{
y
|
y
>
−
9
}
Step-by-step explanation:
Horizontal asymptote- y=-9
Answer:
45,009
Step-by-step explanation:
Answer:
we have
Cos (a+b)=Cos aCosb-SinaSinb
for
Cos (a+a)=Cos aCosa-SinaSina=<u>Cos²a-Sin²a</u>
is a required answer.
Answer: 3/4
Step-by-step explanation: 8/5×15/32 equals 3/4
8/5 * 15/32= Now you must use inverse operations five goes into 15 3Times 8goes into 32 4 times Crossout eight and five cross out 15 and 30 to 3×1 = 3 and 4×1 = 4 so 8/5×15/32 equals 3/4
