If the area is 10 square meters than double that is area of a rectangle with height = 5m and base of 4m because height • base should produce 20m^2.
Hope this helps.
<span>Solve this by substitution:
</span>Solve 5x - 4y = -13 for x:<span><span><span><span>5x </span>− <span>4y </span></span>+ <span>4y </span></span>= -<span>13 + <span>4y </span></span></span>(Add 4y to both sides)
<span><span><u>5x </u></span>= <span><span><u>4y - </u><u>13 </u></span><u> </u> </span></span>(Divide both sides by 5)
5 5
<span>x = <span><span><span><u>4</u></span> y </span>+ -<span><u>13</u><span>
</span></span></span></span> 5 5
You can use https://www.mathpapa.com/algebra-calculator.html
5x - 4y = -13, 8x +10y = 12 (enter both equations with a comma between them and it will solve for you and show you step by step.
Answer:
B (5 sqrt10)
Step-by-step explanation:
If the hypotenuse is 17, and a leg is 8, that makes the other leg equal to sqrt((17^2)-(8^2)) = sqrt(289-64) = sqrt(225) = 15.
Because you subtract 3 from the leg with length 8, that makes the smaller triangles leg 5. That makes the hypotenuse sqrt(5^2 + 15^2) = 5sqrt10
I'm guessing you typoed for B and meant 5sqrt10, so the answer is B
If u can help with this question, the options for both x' s are -8,-7,-6,-5,-4,-3,-2,-1,1,2,3,4,5,6,7,8
Simora [160]
1x + 1y = 100....multiply by -3/8
3/8x + 7/8y = 2000
no need to multiply the other equation by anything....the x's will cancel because one will be -3/8x and one will be 3/8x
Answer:
Rs 120.
Step-by-step explanation:
10=0.85SP-CP; CP+10=0.85SP; SP=[CP+10]/0.85 Eq 1. Let SP= Selling Price and CP= Cost Price
-2 =0.75SP-CP; 0.75SP=C-2; SP=[CP-2]/0.75 Eq 2
[CP+10]/0.85=[CP-2]/0.75 : SP of Eq 1=SP of Eq 2
0.75[CP+10]=0.85[CP-2]
0.75CP+7.5=0.85CP-1.7
0.85CP-0.75CP=-1.7–7.5=9.2
0.10CP=9.2; CP=9.2/0.10
CP=Rs 92 Cost Price of pen
10=0.85SP-92; 0.85SP=92+10=102; SP=102/0.85=Rs 120 Marked Price of pen (answer)
From Eq2: -2=0.75SP-CP; 0.75SP=CP-2=92–2=90; SP=90/0.75=Rs120; -2=0.75(120)-CP; CP-2=0.75(120); CP-2=90; CP=90+2=Rs 92
Set CP of Eq 1=CP of Eq 2:
CP=0.85SP-10 from Eq 1; CP=0.75SP+2 from Eq 2;
0.85SP-10=0.75SP+2; 0.85SP-0.75SP=10+2=12
0.10SP=12; SP=12/0.10=Rs120 is the Marked Price(answer)
Normally, the Selling Price is the marked price. The seller will not disclose the Cost Price because it is the price when the item was acquired or procured, otherwise the buyer will ask for more discounts and based his buying price from the Cost Price if it is known. The calculated SP and CP satisfy both Eq 1 and Eq 2. Both Eq 1 and Eq 2 satisfy the given conditions of the problem above.