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2 years ago

I WILL CHOOSE BRAINLIEST as long as it LOOKS correct Solve 3 ( x − 4 ) = 12 x

Mathematics

2 answers:

Naddika [18.5K]2 years ago

5 0

Answer:

Step-by-step explanation:

3(x - 4) = 12x

Use distributive property: a*(a - b) =(a*b) - (a*c)

3*x - 3*4 = 12x

3x - 12 = 12x

-12 = 12x - 3x

-12 = 9x

9x = -12

x = -12/9 = -4/3

x = -4/3

omeli [17]2 years ago

4 0

Answer:

The answer is (-4/3)

Step-by-step explanation:

3(x − 4) = 12x

Multiply (x – 4) by 3 we get,

3(x – 4) = 12x

3x – 12 = 12x

3x – 12x – 12 + 12 = 12x – 12x + 12

-9x = 12

-9x/(-9) = -12/9

x = -4/3

Thus, The value of x is -4/3

-TheUnknownScientist 72

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4-Fui al supermercado y había un descuento del 15% en el total de la compra, si pagaba en efectivo. Gasté $ 2.400. ¿Qué cantidad

Grace [21]

Answer:

$2.040

Step-by-step explanation:

Para calcular la cantidad que fue abonada en realidad, debes encontrar el valor del descuento calculando el 15% del valor total de la compra y este resultado se debe restar del total:

$2.400*15%= $360

$2.400-$360= $2.040

De acuerdo a esto, la cantidad abonada en realidad es: $2.040.

6 0

3 years ago

What is the solution to the system of equations?

Yuri [45]

Answer:

No solution

Step-by-step explanation:

Note how "2x" shows up in both equations. This suggests doing a substitution to solve the system.

Focus first on the first equation. Solving 2x - y = 7 for 2x, we get:

2x = y + 7.

Next, we substitute y + 7 for 2x in the second equation:

y = (y + 7) + 3.

Simplifying this produces:

0 = 10

This is not true and can never be true. Thus, this system has no solution.

6 0

3 years ago

Read 2 more answers

PLEASE HELP WITH THESE TWO WUESTIONS ILL GIVE BRAINIEST AND GIVE YOU PTS

blondinia [14]

The first one is the same amount of points

4 0

3 years ago

(10 points) Consider the initial value problem y′+3y=9t,y(0)=7. Take the Laplace transform of both sides of the given differenti

Rashid [163]

Answer:

The solution

$Y (s) = 9( -1 +3 t + e^{-3 t} ) + 7 e ^{-3 t}$

Step-by-step explanation:

Explanation:-

Consider the initial value problem y′+3 y=9 t,y(0)=7

Step(i):-

Given differential problem

y′+3 y=9 t

Take the Laplace transform of both sides of the differential equation

L( y′+3 y) = L(9 t)

Using Formula Transform of derivatives

L(y¹(t)) = s y⁻(s)-y(0)

By using Laplace transform formula

$L(t) = \frac{1}{S^{2} }$

Step(ii):-

Given

L( y′(t)) + 3 L (y(t)) = 9 L( t)

$s y^{-} (s) - y(0) + 3y^{-}(s) = \frac{9}{s^{2} }$

$s y^{-} (s) - 7 + 3y^{-}(s) = \frac{9}{s^{2} }$

Taking common y⁻(s) and simplification, we get

$( s + 3)y^{-}(s) = \frac{9}{s^{2} }+7$

$y^{-}(s) = \frac{9}{s^{2} (s+3}+\frac{7}{s+3}$

Step(iii):-

By using partial fractions , we get

$\frac{9}{s^{2} (s+3} = \frac{A}{s} + \frac{B}{s^{2} } + \frac{C}{s+3}$

$\frac{9}{s^{2} (s+3} = \frac{As(s+3)+B(s+3)+Cs^{2} }{s^{2} (s+3)}$

On simplification we get

9 = A s(s+3) +B(s+3) +C(s²) ...(i)

Put s =0 in equation(i)

9 = B(0+3)

B = 9/3 = 3

Put s = -3 in equation(i)

9 = C(-3)²

C = 1

Given Equation 9 = A s(s+3) +B(s+3) +C(s²) ...(i)

Comparing 'S²' coefficient on both sides, we get

9 = A s²+3 A s +B(s)+3 B +C(s²)

0 = A + C

put C=1 , becomes A = -1

$\frac{9}{s^{2} (s+3} = \frac{-1}{s} + \frac{3}{s^{2} } + \frac{1}{s+3}$

Step(iv):-

$y^{-}(s) = \frac{9}{s^{2} (s+3}+\frac{7}{s+3}$

$y^{-}(s) =9( \frac{-1}{s} + \frac{3}{s^{2} } + \frac{1}{s+3}) + \frac{7}{s+3}$

Applying inverse Laplace transform on both sides

$L^{-1} (y^{-}(s) ) =L^{-1} (9( \frac{-1}{s}) + L^{-1} (\frac{3}{s^{2} }) + L^{-1} (\frac{1}{s+3}) )+ L^{-1} (\frac{7}{s+3})$

By using inverse Laplace transform

$L^{-1} (\frac{1}{s} ) =1$

$L^{-1} (\frac{1}{s^{2} } ) = \frac{t}{1!}$

$L^{-1} (\frac{1}{s+a} ) =e^{-at}$

Final answer:-

Now the solution , we get

$Y (s) = 9( -1 +3 t + e^{-3 t} ) + 7 e ^{-3t}$

5 0

3 years ago

Marta hopes to have a test average of at least 90 by the end of the marking period. Her grades on the first four tests have been

Virty [35]

Answer:

Marta need to score at least 94 to receive an average of 90 or higher considering all five tests.

Explanation:

Marks received by Marta in four tests = 86, 84, 97 and 89

Let mark received in fifth test be x

We have average of five test is more than or equal to 90

So we have

$\frac{86+84+97+89+x}{5} \geq 90\\ \\ 86+84+97+89+x\geq 450\\ \\ x\geq 94$

So Marta need to score at least 94 to receive an average of 90 or higher considering all five tests.

5 0

3 years ago