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3 years ago

How to find x in an exponential equation

1 answer:

5 0

If the bases are the same then you can let the exponents be equal to each other. If the exponents are not the same then you will have to use logarithms to solve for x.

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The population of the United States was about 280 million in 2000 and about 310 million in 2010. What was the annual rate of cha

JulsSmile [24]

To find the annual rate of chnge, we have to use the following formula

$\frac{P(2010)-P(2000)}{2010-2000}$

P(2010) represents the population in the year 2010 and P(2000) represents the population in the year 2000 .

Substituting the values, we will get

$\frac{310-280}{2010-2000} = \frac{30}{10} = 3 \ million \ per \ year$

8 0

3 years ago

hey can someone please help me i don’t understand this? the question says “find the surface area of the rectangular prism.”

ASHA 777 [7]

Answer:

170 in^2

Step-by-step explanation:

you have to find the area of each surface of the square

1) the square on the right side:

5x5=25 in^2

there are 2 of these on opposite sides

2)the of the rectangle facing us;

6x5=30in^2 (5 because 5 is the height)

there are 4 of these

3)add up all the areas

25+25+30+30+30+30=170in^2

6 0

3 years ago

the graph of a linear function is given below. What is the zero of the function? a) -5. b) 2/5. c) 2. d) 5/2

Murrr4er [49]

The zero of a function is the x-value at which the function value is zero. That is, the value of the function that intersects the x-axis. From the picture, the zero is -5

4 0

1 year ago

A drinking cup in the shape of a cone has a height of 5 in, and a radius of 3.5 in. If the

IrinaK [193]

Geometry helps people understand life u are short and don’t know how life helps u

3 0

2 years ago

Integrate 1 - x / x(x2 + 1) d x by partial fractions.

solniwko [45]

Answer:

$log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x$

Step-by-step explanation:

step 1:- by using partial fractions

$[tex]\frac{1-x}{x(x^{2}+1) } =\frac{A(x^{2}+1)+(Bx+C)(x }{x(x^{2}+1) }$ ......(1)

step 2:-

solving on both sides

$1-x=A(x^{2} +1)+(Bx+C)x......(2)$

substitute x =0 value in equation (2)

1=A(1)+0

A=1

comparing x^2 co-efficient on both sides (in equation 2)

0 = A+B

0 = 1+B

B=-1

comparing x co-efficient on both sides (in equation 2)

-1 = C

step 3:-

substitute A,B,C values in equation (1)

now

$\\\int\limits^ {} \, \frac{1-x}{x(x^{2}+1) } d x =\int\limits^ {} \frac{1}{x} d x +\int\limits^ {} \frac{-x}{x^{2}+1 } d x -\int\limits \frac{1}{x^{2}+1 } d x$

by using integration formulas

i) by using $\int\limits \frac{1}{x} d x =log x+c........(a)\\\int\limits \frac{f^{1}(x) }{f(x)} d x= log(f(x)+c\\$ .....(b)

$\int\limits tan^{-1}x dx =\frac{1}{1+x^{2} } +C$ .....(c)

step 4:-

by using above integration formulas (a,b,and c)

we get answer is

$log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x$

6 0

3 years ago