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3 years ago

6

What number is divisible by five 970 729 86 or 52

1 answer:

madam [21]3 years ago

5 0

Any number the one digit equal 5 or 0 can divide by 5

so answer is 970

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The numbers 2/1/3,h,k,7/7/8 firm a geometric progression. find the value of h and of k

taurus [48]

$\text{We have }\ 2\dfrac{1}{3},\ h,\ k,\ 7\dfrac{7}{8}.\\\\\text{Convert the mixed numbers to the improper fractions}\\\\2\dfrac{1}{3}=\dfrac{2\cdot3+1}{3}=\dfrac{7}{3}\\\\7\dfrac{7}{8}=\dfrac{7\cdot8+7}{8}=\dfrac{63}{8}\\\\\text{If}\ a_1,\ a_2,\ a_3,\ a_4\ \text{is a geometric seqence, then:}\\\\\dfrac{a_2}{a_1}=\dfrac{a_3}{a_2}=\dfrac{a_4}{a_3}=r\\\\a_2=a_1r\\\\\text{and}\ \dfrac{a_4}{a_1}=r^3\\\\\text{Substitute:}$

$r^3=\dfrac{\frac{63}{8}}{\frac{7}{3}}\\\\r^3=\dfrac{63}{8}\cdot\dfrac{3}{7}\\\\r^3=\dfrac{9\cdot3}{8\cdot1}\\\\r^3=\dfrac{27}{8}\to r=\sqrt[3]{\dfrac{27}{8}}\\\\r=\dfrac{3}{2}\\\\h=2\dfrac{1}{3}\cdot\dfrac{3}{2}=\dfrac{7}{3}\cdot\dfrac{3}{2}=\dfrac{7}{2}\\\\k=\dfrac{7}{2}\cdot\dfrac{3}{2}=\dfrac{21}{4}\\\\Answer:\ \boxed{h=\dfrac{7}{2}=3\dfrac{1}{2}\ and\ k=\dfrac{21}{4}=5\dfrac{1}{4}}$

8 0

3 years ago

Two supplementary angles are in the ratio 3 1 : 5 find both angles

Zielflug [23.3K]

The two angles are 155 degrees and 25 degrees

<h3><u>Solution:</u></h3>

Given that two supplementary angles are in ratio 31 : 5

Let the first angle be 31a

Let the second angle be 5a

Two Angles are Supplementary when they add up to 180 degrees.

Therefore,

first angle + second angle = 180 degrees

$31a + 5a = 180\\\\36a = 180\\\\a = \frac{180}{36}\\\\a = 5$

<em><u>Therefore the angles are:</u></em>

first angle = 31a = 31(5) = 155 degrees

second angle = 5a = 5(5) = 25 degrees

Thus the two angles are 155 degrees and 25 degrees

3 0

3 years ago

Simplify the following expression.<br><br> 99 - 3[15 - (2 + 1)]

Vikki [24]

Answer:

63

Step-by-step explanation:

2+1= 3

15-3= 12

12 x 3 = 36

99 - 36

= 63

6 0

3 years ago

Read 2 more answers

Find the area of a rectangle that has the length of 2x-3 and the width of x .Someone painted an interior area of the rectangle a

Svet_ta [14]

Answer:

The area that was not painted is $(2x^{2}-6x+6)\ units^{2}$

Step-by-step explanation:

step 1

Find the area of the rectangle

we know that

The area of a rectangle is equal to

$A=LW$

In this problem we have

$L=2x-3$

$W=x$

substitute

$A=(2x-3)x\\A=(2x^{2}-3x)\ units^{2}$

step 2

Find the area that was painted

$A=(3)(x-2)\\A=(3x-6)\ units^{2}$

step 3

Find the area that was not painted

Subtract the area that was painted from the total area of rectangle

so

$A=(2x^{2}-3x)-(3x-6)=(2x^{2}-6x+6)\ units^{2}$

8 0

3 years ago

Divide the following polynomial expression.<br><br> (n^4 +5n^3+9n^2) / 9n^3

Serhud [2]

Dhjdjdjdjdjdjndjdjdjdjdjdjjsjdjdjdjd

6 0

2 years ago