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3 years ago

What is the definition for Interquartile Range

Mathematics

1 answer:

Molodets [167]3 years ago

3 0

The answer is C, because to find IQR you have to find the difference (subtract) of the first and third quartile

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Please help and show step by step

kenny6666 [7]

1. Find 70% of 100. 100 x 0.70 = 70.
2. Find 60% of 70. 70 x 0.60 = 42.
3. The answer is 42. Hope that helps!

6 0

3 years ago

Read 2 more answers

3/10+21/100 as a fraction

adell [148]

Answer:

51/100

Step-by-step explanation:

3/10 + 21/100
=> 30/100 + 21/100
=> 51/100

Conclusion:

Therefore, 3/10 + 21/100 equals 51/100 as a fraction.

Hoped this helped.

$BrainiacUser1357$

7 0

2 years ago

Read 2 more answers

Suppose the teacher surveys one student at random. Based on the survey results, what is the estimated probability that the stude

lys-0071 [83]

Answer:

50% probably

Step-by-step explanation:

well how many options are there

think 1/? ? being how many options there are and 1 being the 1 option to pick aquarium

3 0

3 years ago

Help !!!!!!!!!!!!!!!!!

valina [46]

C is a subset of D
This is because all of the elements of set C, is also included in set D.

6 0

3 years ago

Find the sum of the measures of the interior angles of each of the following convex polygons: a pentagon, an octagon, a dodecago

TiliK225 [7]

Answer:

$540^{\circ},\ 1080^{\circ},\ 1800^{\circ},\ 6840^{\circ},\ 9000^{\circ},\ 17640^{\circ}$

Step-by-step explanation:

The sum of the measures of the interior angles of each convex n-sided polygon is always equal to

$(n-2)\cdot 180^{\circ}.$

1. A pentagon is 5-sided polygon, then the sum of the measures of the interior angles of pentagon is

$(5-2)\cdot 180^{\circ}=540^{\circ}.$

2. An octagon is 8-sided polygon, then the sum of the measures of the interior angles of octagon is

$(8-2)\cdot 180^{\circ}=1080^{\circ}.$

3. A dodecagon is 12-sided polygon, then the sum of the measures of the interior angles of dodecagon is

$(12-2)\cdot 180^{\circ}=1800^{\circ}.$

4. For 40-sided polygon the sum of the measures of the interior angles is

$(40-2)\cdot 180^{\circ}=6840^{\circ}.$

5. For 52-sided polygon the sum of the measures of the interior angles is

$(52-2)\cdot 180^{\circ}=9000^{\circ}.$

6. For 100-sided polygon the sum of the measures of the interior angles is

$(100-2)\cdot 180^{\circ}=17640^{\circ}.$

5 0

4 years ago