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3 years ago

15

What is the definition for Interquartile Range

1 answer:

Molodets [167]3 years ago

3 0

The answer is C, because to find IQR you have to find the difference (subtract) of the first and third quartile

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Please help please please please

Readme [11.4K]

It is a low posabilaty

8 0

4 years ago

two cars travel at same speed to different destinations. car A reaches its destination in 24 minutes. car B reaches its destinat

Harlamova29_29 [7]

Answer:

The speeds of the cars is: 0.625 miles/minute

Step-by-step explanation:

We use systems of equations in two variables to solve this problem.

Recall that the definition of speed (v) is the quotient of the distance traveled divided the time it took : $v=\frac{distance}{time}$ . Notice as well that the speed of both cars is the same, but their times are different because they covered different distances. So if we find the distances they covered, we can easily find what their speed was.

Writing the velocity equation for car A (which reached its destination in 24 minutes) is:

$v\,*\,24\,min=d_A$

Now we write a similar equation for car B which travels 5 miles further than car A and does it in 32 minutes:

$v\,*\,32\,min=d_A+5\,miles$

Now we solve for $d_A$ in this last equation and make the substitution in the equation for car A:

$v\,*\,32\,min=d_A+5\,miles\\d_A=v\,*\,32\,min-5\,miles\\\\v\,*\,24\,min=v\,*\,32\,min-5\,miles\\v\,(24\,min-32\,min)=-5\,miles\\v\,(-8\,min)=-5\, miles\\v=\frac{-5}{-8} \frac{miles}{min} \\v=0.625\,\frac{miles}{min}$

So this is the speed of both cars: 0.625 miles/minute

3 0

4 years ago

HELP PLSSSSSSSSSSSSSSSSSSSSSSSS

velikii [3]

I would go withhh c but I am not 100% sure

6 0

3 years ago

the stove you have to bake in is an old one and only has the temperature in ° Fahrenheit. You are making rusks and have to dry t

nalin [4]

Answer:

$80^{\circ} C$

Step-by-step explanation:

You are making rusks and have to dry them overnight at a temperature of 176° F.

The given temperature is in Fahrenheit. We need to convert it into °C.

The relation between Fahrenheit and °C is given by :

$C=\dfrac{5}{9}(F-32)$

Put F = 176

So,

$C=\dfrac{5}{9}(176-32)\\\\C=\dfrac{5}{9}\times 144\\\\C=80^{\circ} C$

So, the temperature is equal to $80^{\circ} C$ .

3 0

3 years ago

In a parenting magazine, Mrs. Smith read an advertisement about all the different ways that bleach can be used to kill bacteria.

babymother [125]

Question:

(a) How many bacteria would be found in 24 hours

(b) How many bacteria would be found in 2 days

(c) How long for 1000 bacteria to be found

Answer:

(a) 282429536481 bacteria

(b) $7.97*10^{22$ bacteria

(c) 6 days

Step-by-step explanation:

The question illustrates an exponential function

$y = ab^x$

Where

$a = Initial\ Value = 1$

$b=Rate = 3$ --- i.e. triples

$x = number\ of\ hours$

Solving (a): Bacteria in 24 hours

In this case:

$x = 24$

Substitute $x = 24$ , $b = 3$ and $a = 1$

So:

$y = ab^x$

$y = 1 * 3^{24$

$y = 1 * 282429536481$

$y = 282429536481$ bacteria

Solving (b): Bacteria in 2 days

$2\ days =48\ hours$

So:

$x = 48$

Substitute $x = 48$ , $b = 3$ and $a = 1$

So:

$y = ab^x$

$y = 1 * 3^{48$

$y =7.97*10^{22$ bacteria

Solving (c): How long for 1000 bacteria

In this case:

$y = 1000$

Substitute $y = 1000$ , $b = 3$ and $a = 1$

So:

$y = ab^x$

$1000 = 1 *3^x$

$1000 = 3^x$

Take Log of both sides

$Log1000 = Log3^x$

This gives:

$Log1000 = xLog3$

Make x the subject

$x = \frac{Log1000}{Log3}$

$x \approx 6$

<em>Hence: It takes 6 days</em>

8 0

3 years ago