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NNADVOKAT [17]
2 years ago
14

Can anyone help me please, I will mark brainliest to the right answer

Mathematics
1 answer:
Blababa [14]2 years ago
3 0

Answer:

y-4=0

Step-by-step explanation:

its the only that doesn't have a x?

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I undermost of my problems but i dont get this one. any help?
Mnenie [13.5K]

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Alexxandr [17]
To take out terms outside the radical we need to divide the power of the term by the index of the radical; the quotient will be the power of the term outside the radical, and the remainder will be the power of the term inside the radical. 
First, lets factor 8:
8=2 ^{3}
Now we can divide the power of the term, 3, by the index of the radical 2:
\frac{3}{2} = 1 with a remainder of 1
Next, lets do the same for our second term x^{7}:
\frac{7}{2} = 3 with a remainder of 1
Again, lets do the same for our third term y^{8}:
\frac{8}{2} =4 with no remainder, so this term will come out completely.

Finally, lets take our terms out of the radical:
\sqrt{8x^{7} y^{8}  }= \sqrt{ 2^{3} x^{7} y^{8}   }  =2 x^{3}  y^{4}  \sqrt{2x}

We can conclude that the correct answer is the third one. 

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3 years ago
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