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2 years ago

What is 9x8+43 free brainliest

Mathematics

2 answers:

jenyasd209 [6]2 years ago

7 0

$\: \:$

$\:$

$\huge \frak{9 \times 8 + 43 = }$

$\: \:$

$\huge \frak{72 + 43 = }$

$\: \:$

$\boxed{ \huge \frak{ \gray{115}}}$

$\: \: \:$

Hope Helps! :)

quester [9]2 years ago

3 0

Answer:

115

Step-by-step:

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PLEASE HELP PLEAsee before It’s due

xz_007 [3.2K]

The measure of BOC is 47

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3 years ago

Ken has already baked 4 pies and he can bake 1 pie with each additional cup of sugar he buys. With 31 additional cups of sugar,

Bumek [7]

Answer: 35 pies

Step-by-step explanation:

Ken can bake 1 pie with each additional cup of sugar he buys. 1 pie =1 cup

4 + x = y

Where;

x= additional pies

y= total pies

If 1 cup= 1 pie; then 31 cups =

31 cup × 1 pie/1 cup = x

:. x= 31 pies

y= x + 4

y= 31+4 = 35

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3 years ago

Can someone explain to me how to do this

rusak2 [61]

rank | 1st | 2nd |TOTAL
------|-----+-------|----------
a | 6 +    9 | =15
b | 7 + 3    | =16
c | 9 + 7    | =23
d | 6 + 7    | =22
e | 8 + 1 | =?

If you add the 1st in line a (6) and you add it to the 1st in line b (7) + the 2nd in line b (3) you get 16. Repeat the same logic/pattern to all c,d..
This is the pattern to all this puzzle;

So the before last term is : 9+6+7 = 22
and the last term : 6+8+1 = 15

7 0

3 years ago

Silicon wafers are scored and then broken into the many small microchips that will he mounted into circuits. Two breaking method

antoniya [11.8K]

Answer:

The estimate is $- 0.0265\le K \le 0.0465$

Method B this is because the faulty breaks are less

Step-by-step explanation:

The number of microchips broken in method A is $n_1 = 400$

The number of faulty breaks of method A is $X_1 = 32$

The number of microchips broken in method B is $n_2 = 400$

The number of faulty breaks of method A is $X_2 = 32$

The proportion of the faulty breaks to the total breaks in method A is

$p_1 = \frac{32}{400}$

$p_1 = 0.08$

The proportion of the faulty to the total breaks in method B is

$p_2 = \frac{28}{400}$

$p_2 = 0.07$

For this estimation the standard error is

$SE = \sqrt{ \frac{p_1 (1 - p_1)}{n_1} + \frac{p_2 (1- p_2 )}{n_2} } }$

substituting values

$SE = \sqrt{ \frac{0.08 (1 - 0.08)}{400} + \frac{0.07 (1- 0.07 )}{400} } }$

$SE = 0.0186$

The z-values of confidence coefficient of 0.95 from the z-table is

$z_{0.95} = 1.96$

The difference between proportions of improperly broken microchips for the two breaking methods is mathematically represented as

$K = [p_1 - p_2 ] \pm z_{0.95} * SE$

substituting values

$K = [0.08 - 0.07 ] \pm 1.96 *0.0186$

$K = - 0.0265 \ or \ K = 0.0465$

The interval of the difference between proportions of improperly broken microchips for the two breaking methods is

$- 0.0265\le K \le 0.0465$

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2 years ago

Find the prime factors.<br> 7) 48

FinnZ [79.3K]

Step-by-step explanation:

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2 years ago